Answer:
6.86 N
Explanation:
Applying,
F = mg............... Equation 1
Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity
Note: The Force exerted by gravity on the mass is thesame as the weight of the body.
From the question,
Given: m = 700 g = (700/1000) = 0.7 kg
Constant: g = 9.8 m/s²
Substitute these values into equation 1
F = 9.8(0.7)
F = 6.86 N
The velocity of the submarine immediately after firing the missile is 0.0104 m/s
Explanation:
Mass of the submarine M=50 tonne=
Mass of the missile m=40 kg
velocity of the missile v= 13m/s
we have to calculate the velocity of the submarine after firing
This is the recoil velocity and its expression is derived from the law of conservation of momentum
recoil velocity of the submarine
Answer:
C
Explanation:
If Ami is saying she likes it then it it personal. If you are speaking from statistics and studies it is impersonal and technically not from there perspective. All of these do this except C.
Answer:
option B
−1.92 m/s2
Explanation:
Given in the question,
time took by truck to slow down = 3.56 sec
initial speed of truck = 112 km/h
final speed of truck = 87.4 km/h
1 km/h = 0.277778 m/s
112 = 31.1 m/s
87.4 = 24.28 m/s
Formula use to calculate the acceleration
v - u = at
where v is final speed
u is initial speed
a is acceleration
t is time
plug values in the equation
24.28 - 31.1 = a(3.56)
-6.8 = a(3.56)
a = -6.8 / 3.56
a = -1.9 m/s²
