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Goryan [66]
3 years ago
7

This mathematical model describes the changes that occur in a sample of water as its temperature increases. Based on this model,

how do you expect the motion of the molecules in ice to compare with the motion of molecules in water vapor?
A. I expect the molecules in ice to move more quickly than the molecules in water vapor.
B. This model does not provide enough data to answer the question.
C. I expect the motion to be very similar.
D. I expect the molecules n water vapor to move more quickly than the molecules in ice.

Physics
2 answers:
Sergio039 [100]3 years ago
7 0

Answer:A. I expect the molecules in ice to move more quickly than the molecules in water vapor.

Explanation:

pychu [463]3 years ago
6 0

Answer: apex = D

Explanation:

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To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

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With the previous values the area of the muscle (Real Muscle-82%)is,

A_m = (0.82)\pi r^2 = (0.82)\pi (12/2*10^{-2})^2

A_m = 9.274*10^{-3}m^2

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R_m = \rho \frac{L}{A}

R_m = \frac{13*(0.4)}{9.274*10^{-3}}

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At the same time we can make the same process to calculate the resistance of the fat, then

A_m = (0.18)\pi r^2 = (0.18)\pi (12/2*10^{-2})^2

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The resistance of the fat would be,

R_f = \rho \frac{L}{A}

R_f = \frac{25*(0.4)}{2.0357*10^{-3}}

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R = 502.62\Omega

We can here apply Ohm's law, then

I= \frac{V}{R}

I = \frac{1.5}{502.62}

I = 2.984*10^{-3}A

I = 2.984mA

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