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Zinaida [17]
3 years ago
11

Seawater is 3.5% Sodium Chloride by mass. Sea Salt can contain about 10 % water.

Chemistry
2 answers:
Mekhanik [1.2K]3 years ago
6 0

10g water is removed from every Kilogram of Commercial Sea Salt

Zielflug [23.3K]3 years ago
3 0

Answer:

900 g

Explanation:

90% of 1000 g is 900g

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3 years ago
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<span>0.06355391 mol The balanced equation for the reaction is Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O So for each mole of Borax to neutralize, it takes 2 moles of HNO3. Calculate number of moles of Borax 0.2619 g / 381.372 g/mol = 0.0006867 mol Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So 0.0013734 / 0.02161 = 0.06355391 mol</span>
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