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Serga [27]
2 years ago
15

How many atoms are in 9.44 moles of Al?

Chemistry
2 answers:
harina [27]2 years ago
8 0
The answer is D which is 23
BlackZzzverrR [31]2 years ago
4 0

Answer:

c) %5.68×10²⁴

Explanation:

Number atoms=Avogadro's number ₓ number of moles

N= 6.023ₓ 10²³×9.44

N=5.68×10²⁴

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Calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 x 1023 molecules)
Ainat [17]

Hey there!

Molar mass N2 = 28.01 g/mol

Therefore:

28.01 g N2 -------------- 6.02*10²² molecules N2

( mass N2 ?? ) ----------- 25,000 molecules N2

mass N2 =  ( 25,000 * 28.01 ) /  ( 6.02*10²³ )

mass N2 = 700250 / 6.02*10²³

mass N2 = 1.163*10⁻¹⁸ g


Hope that helps!

7 0
3 years ago
Read 2 more answers
Which statement describes both homogeneous mixtures and heterogeneous mixtures?
stiks02 [169]

Answer:

both are the types of mixture and both are impure substances that donot have fixed composition and the composition of constituents  is not uniform

5 0
3 years ago
Which of the following terms means that metals can be pulled into thin strands or wires? [like copper]
Dimas [21]

Answer:

D

Explanation:

plz mark brainliest answer if it helps

5 0
2 years ago
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A material through which heat travels easily is what
Bogdan [553]

Heat moves easily through good conductors of heat (such as metals) and very slowly through heat insulators (such as wood or plastic).

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3 0
3 years ago
Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise
USPshnik [31]

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

Initial:          0.110                  -             -

change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

But final = 0.150atm;

0.110 - 2x    +  4x   +  x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k =  rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3)  t

upon solving, t = 37.1 s

3 0
3 years ago
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