How many atoms are in 9.44 moles of Al?
2 answers:
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The relative volumes of chloroform and water that should be used is 9:10
Concentration of solution in chloroform = ( moles of chloroform )
Concentration of solution in water = ( moles of water )
Dissociation constant at ;
Concentration of solution in chloroform / Concentration of solution in water
Meaning;
Since mole is present in chloroform and
mole is present in water, Total mole of Caffeine present is
Now, we substitute our given values into the equation
Therefore, the relative volumes of chloroform and water that should be used is 9:10
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The concentration of that should used originally is
Explanation:
From the question we are told that
The necessary elementary step is
The time taken for sixth of 0.5 M of reactant to react
The time available is
The desired concentration to remain
Let Z be the reactant , Y be the first product and X the second product
Generally the elementary rate law is mathematically as
Where k is the rate constant , is the concentration of Z
From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )
For second order reaction
Where is the initial concentration of Z which a value of
From the question we are told that it take 9 hours for the concentration of the reactant to become
So
=>
For
The structures of the isomers and the m/z values of their peaks are not given in the question. The complete question is provided in the attachment
Answer:
Compound 2 (2,5-dimethylhexane) will not have the peaks at 29 and 85 m/z
Explanation:
The fragmentation of molecules by electron ionization of mass spectrometer occurs according to Stevenson's Rule, which states that "The most probable fragmentation is the one that leaves the positive charge on the fragment with the lowest ionization energy". This is much like the Markovnikov's Rule in organic chemistry which has predicted the formation of most stable carbocation and the addition of hydrogen halide to it.
The mass spectra of compound 1 (2,4-dimethylhexane) will contain all the m/z values mentioned in the question. Each peak indicate towards homologous series of fragmentation product of the compound 1. The first peak can be attributed to ethyl carbocation (m/z = 29), with the increase of 14 units the next peak indicates towards propyl carbocation (m/z = 43) and onwards until molecular ion peak of 114 m/z.
Compound 2 (2,5-dimethylhexane) structure shows that the cleavage of C-C bond will not yield a stable ethyl and hexyl carbocation. Hence, no peaks will be observed at 29 and 85 m/z. The absence of these two peaks can be used to distinguish one isomer from the other.
