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Oliga [24]
3 years ago
9

How many moles of NO3 are there in 6.2g?

Chemistry
2 answers:
Kitty [74]3 years ago
5 0

Answer : The number of moles of NO_3 is, 0.1 moles

Solution : Given,

Mass of NO_3 = 6.2 g

Molar mass of NO_3 = 62 g/mole

Now we have to calculate the moles of NO_3.

\text{Moles of }NO_3=\frac{\text{Mass of }NO_3}{\text{Molar mass of }NO_3}=\frac{6.2g}{62g/mole}=0.1moles

Therefore, the number of moles of NO_3 present in 6.2 g is, 0.1 moles

Nataliya [291]3 years ago
3 0
6.2 divided by the mass number of NO3 is 0.1 moles. Anytime your trying to find the moles of something you divide it by the mass number of your combined elements.
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Is there any other part to this question? If not I'm pretty sure the answer is 205.5 kJ

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(molecular) 3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) +  6 NH₄Cl(aq)

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The molecular equation includes al the species in the molecular form.

3 CaCl₂(aq) + 2 (NH₄)₃PO₄(aq) ⇄ Ca₃(PO₄)₂(s) +  6 NH₄Cl(aq)

The ionic equation includes all the ions (species that dissociate in water) and the species that do not dissociate in water.

3 Ca²⁺(aq) + 6 Cl⁻(aq) + 6 NH₄⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s) + 6 NH₄⁺(aq) + 6 Cl⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the species that do not dissociate in water. In does not include <em>spectator ions</em>.

3 Ca²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Ca₃(PO₄)₂(s)

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