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Oliga [24]
3 years ago
9

How many moles of NO3 are there in 6.2g?

Chemistry
2 answers:
Kitty [74]3 years ago
5 0

Answer : The number of moles of NO_3 is, 0.1 moles

Solution : Given,

Mass of NO_3 = 6.2 g

Molar mass of NO_3 = 62 g/mole

Now we have to calculate the moles of NO_3.

\text{Moles of }NO_3=\frac{\text{Mass of }NO_3}{\text{Molar mass of }NO_3}=\frac{6.2g}{62g/mole}=0.1moles

Therefore, the number of moles of NO_3 present in 6.2 g is, 0.1 moles

Nataliya [291]3 years ago
3 0
6.2 divided by the mass number of NO3 is 0.1 moles. Anytime your trying to find the moles of something you divide it by the mass number of your combined elements.
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1. Using the Slater rule, determine the effective nuclear charge of platinum.
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Answer:

Z* = 3.55

Explanation:

Slater rule says that:

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The first Slater rule says that we need to group:

(1s^{2}) (2s, 2p)^{8} (3s, 3p)^{8} (3d^{10}) (4s, 4p)^{8} (4d^{10}) (5s, 5p)^{8} (4f^{14}) (5d^{9}) (6s^{1})

The second rule says that the electrons to the right are not shielding, but we are going to solve the exercise for the last level (6s), so we don't have electrons to the right.

For the third rule we have two considerations, if is ns or np and if is nd or nf:

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-electrons within the n-1 group shield 0.85

-electrons within the n-2 or lower groups shield 1.00

Now we can proceed with the calculation:

The first consideration in the third rule does not apply as we only have one electron on this level.

The second consideration will be as follow for the level 5, where we have 17 electrons.

Finally the third consideration will be for levels 1, 2, 3 and 4, where we have 14 for 4f, 10 for 4d, 8 for 4s and 4p, 10 for 3d, 8 for 3s and 3p, 8 for 2s and 2p and finally 2 for 1s, which gives 60 electrons.

So the result for S=(60*1.00 + 17*0.85) = 74.45

And the equation is: Z* = 78 - 74.45

So Z* = 3.55

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