Do parentheses first: 9+7x4-6/3 then multiplication/division: 9+28-2 then addition/subtraction: =35
Answer: y = -4/3x + 0. Yes, that point lies on the line
Step-by-step explanation:
Use this equation, Δy/Δx and this one, y = mx + b. Or, change in the y value divided by the change in the x value.
-4 + 8 = 4
3 - 6 = -3
The slope, m, is -4/3. Now solve for b by plugging in the slope.
. B is equal to 0
To see if that point lies on the function, plug it in the equation and see if it is true. Multiply -4 x -3 to get 12, divide by 3 to get 4, then add 0. The equation says that 4 = 4, which is infact true
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Monthly fee = $17
Additional fee per unit of use = $0.05
Least amount she's been charged in a month = $83.90
Equation to represent the number of minutes 'M':
monthly fee + (additional fee per minute × M) = $83.90
Possible number of minutes :
83.90 ≤ $17 + 0.05M
$17 + $0.05 × M = $83.90
$0.05*M = $83.90 - $17
$0.05*M = $66.90
M = $66.90 / 0.05
M = 1,338 minutes
X=13/15. Subtract 8x from both sides to get 3x=13/5. Divide both sides by 3 or multiple both sides by 1/3 to get x=13/15.
Answer:
The two column proof can be presented as follows;
Statement
Reason
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines
3. ∠9 ≅ ∠11
Transitive property of equality
4. a║b
Corresponding angles on parallel lines are congruent
Step-by-step explanation:
The statements in the two column proof can be explained as follows;
Statement
Explanation
1. p║q
Given
∠1 ≅ ∠11
2. ∠1 ≅ ∠9
Corresponding angles on parallel lines crossed by a common transversal are congruent
3. ∠9 ≅ ∠11
Transitive property of equality
Given that ∠1 ≅ ∠11 and we have that ∠1 ≅ ∠9, then we can transit the terms between the two expressions to get, ∠9 ≅ ∠11 which is the same as ∠11 ≅ ∠9
4. a║b
Corresponding angles on parallel lines are congruent
Whereby we now have ∠9 which is formed by line a and the transversal line q, is congruent to ∠11 which is formed by line b and the common transversal line q, and both ∠9 and ∠11 occupy corresponding locations on lines a and b respectively which are crossed by the transversal, line q, then lines a and b are parallel to each other or a║b.