Answer:
a) y = -6/x has a vertical asymptote at x = 0
b) y = 1/(2·x) - 1 has two asymptotes;
1) A vertical asymptote at x = 0
2) A horizontal asymptote at y = -1
Step-by-step explanation:
The asymptote is given as the line in which the distance between the graph and the line draws closer to zero as either the 'x', or 'y', or both 'x', and 'y', approaches infinity
a) The given equation is y = -6/x
Therefore, the function does not have a horizontal or oblique asymptote only a vertical asymptote at x = 0
b) The given equation is y = 1/(2·x) - 1
∴ y = (1 - 2·x)/(2·x)
The function has a vertical asymptote at x = 0
The function has an horizontal asymptote at y = -2/2 = -1
The answer would be -10p64q^1
since -10^3(p^4)^3 (q^1)^3 is -1000p^12q^3
Answer:
Step-by-step explanation:
Let
r ----> the number of readers (y-coordinate or dependent variable)
t ----> the number of years after 2000 (x-coordinate or independent variable)
Remember
2004 ----> represent t=4 years
2014 ----> represent t=14 years
we have the ordered pairs
(4,1,000,000) and (14,2,000,000)
step 1
Find the slope
The formula to calculate the slope between two points is equal to
substitute the values
step 2
Find the equation of the line in point slope form
we have
substitute
step 3
Convert to slope intercept form
isolate the variable r
step 4
Convert to function notation
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