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lidiya [134]
3 years ago
8

Analyze the explanation and identify any false statements. Each statement to be analyzed is identified by a capital letter. A ba

l is rotating in a horizontal plane on the end of a string of length I. (A) The rotational kinetic energy remains constant as long as the length and angular speed are fixed. (B) When the ball is pulled inward and the length of the string is shortened, the rotational kinetic energy will remain constant due to conservation of energy, (C) but the angular momentum L will not remain constant because there is an external force acting on the ball to pull it inward. (D) The moment of inertia I remains constant (E) the angular speed will remain the same throughout the process because the ball is rotating in the same plane throughout the motion.
Physics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

Explanation:

The rotational kinetic energy remains constant as long as the length and angular speed are fixed.

Statement A is true.

When the ball is pulled inward and the length of the string is shortened, the rotational kinetic energy will remain constant due to conservation of energy,

Statement B is false .

Reason - Conservation of energy will not be there because external work is done on the system  by the force that pulls it inward.  

but the angular momentum L will not remain constant because there is an external force acting on the ball to pull it inward

Statement C is false .

Reason - the angular momentum L will remain constant because there is an external force acting on the ball which acts perpendicular to the velocity of the ball .

The moment of inertia I remains constant

Statement D is false

Reason - because distance from axis of rotation is changing.

the angular speed will remain the same throughout the process because the ball is rotating in the same plane throughout the motion.

Statement E is false

Reason - Since moment of inertia decreases , to conserve angular momentum , angular speed increases.

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Answer:

18.65

Explanation:

To solve, divide 1865 by 100

1865/100= 18.65

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3 years ago
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A cart of mass m moving right at speed v with respect to the track collides with a cart of mass 0.7m moving left.
Zolol [24]

Answer:

10v / 7

Explanation:

Using the conservation law of momentum

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m v - 0.7 m v₁ =  ( 0.7 m + m) 0 m/s since the cart stuck together after collision. taken right to be positive and left to be negative

m v - 0.7 m v₁ = 0

- 0.7 m v₁ = -m v

v₁ = -m v / - 0.7 m = 10v / 7

5 0
4 years ago
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In a RLC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o
Marrrta [24]

Answer:

<h2>Case i) if \omega L > \frac{1}{\omega c}</h2><h2>So initially if the circuit is inductive in nature then its net impedance will decrease after this</h2><h2>Case ii) if \omega L < \frac{1}{\omega c}</h2><h2>So initially if the circuit is capacitive in nature then its net impedance will increase after this</h2>

Explanation:

As we know that the impedance of the circuit is given as

z = \sqrt{(\omega L - \frac{1}{\omega c})^2 + R^2}

when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination

c_{eq} = c_1 + c_2

so it is

c_{eq} = 2c

now we have

z = \sqrt{(\omega L - \frac{1}{2\omega c})^2 + R^2}

Case i) if \omega L > \frac{1}{\omega c}

So initially if the circuit is inductive in nature then its net impedance will decrease after this

Case ii) if \omega L < \frac{1}{\omega c}

So initially if the circuit is capacitive in nature then its net impedance will increase after this

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3 years ago
The atomic particle that has a charge opposite to that of an electron is called a
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A proton (+).
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3 years ago
A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.3 N-s and the ball starts with an initial horizont
Georgia [21]

Answer:

141.30grams

Explanation:

First, denote our known values;

J=1.3N-s(+,east)\\u=-3.8ms^-^1(-,west)\\v=5.4ms^-^1(+,east)\\m=?

Mass is impulse divided by change in velocity:

m=\frac{J}{v-u}\\=\frac{1.3}{5.4--3.8}\\\\=\frac{1.3}{9.2}\\=0.1413Kgs

Hence, the mass of the ball is 141.30grams

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3 years ago
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