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umka2103 [35]
3 years ago
11

A plane mirror and a concave mirror (f = 8.20 cm) are facing each other and are separated by a distance of 25.0 cm. An object is

placed between the mirrors and is 12.5 cm from each mirror. Consider the light from the object that reflects first from the plane mirror and then from the concave mirror. What is the distance of the image (di) produced by the concave mirror?
Physics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

Sol: - I1: Reflexión a la distancia del primer espejo del objeto = 5 cm a la derecha ==> distancia de la imagen = 5 cm a la izquierda Ahora, I2: Reflexión al espejo 2 distancia del objeto = 20-5 = 15 cm a la izquierda == > distancia de imagen = 15 cm a la derecha Ahora, I3: la imagen I2 será como objeto para el espejo 1 distancia de objeto = 15 + 20 = 35 cm a la derecha ==> distancia de imagen = 35 cm a la izquierda Ahora, I4: I1 la imagen será como objeto para el espejo 2 distancia del objeto = 5 + 20 = 25 cm a la izquierda ==> distancia de la imagen = 25 cm a la derecha Ahora, I5: la imagen I4 será como objeto para la distancia del espejo 1 ...

Explanation:

Dafna11 [192]3 years ago
6 0

Answer:

The distance of image formed by the concave mirror is at 10.495 cm.

Explanation:

Since we know that a plane mirror forms image at a distance behind the mirror at which the object is placed in front of the mirror thus we have.

Image formed by the plane mirror is at a distance of 12.5 cm behind the plane mirror.

The image formed by the plane mirror is at a distance of 12.5 + 25.0 = 37.5 cm  from the pole of the concave mirror.

Thus by  mirror formula we have

\frac{1}{v}+\frac{1}{u}=\frac{1}{f}

Using the standard sign convention we have

u = location of object = -37.5 cm

f = focal length of mirror = -8.20 cm

Thus using the given values we obtain

\frac{1}{v}+\frac{1}{-37.5}=\frac{1}{-8.2}\\\\\therefore v=-10.495cm

Thus the image is formed at a distance of 10.495 cm from the pole of mirror towards left of mirror.

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Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at c is 3.39 m/s and
djverab [1.8K]

The magnitude of the average friction force exerted on the collar (F)=  8.641 N

<h3>How can we calculate the magnitude of the average friction force exerted on the collar?</h3>

To calculate the magnitude of the average friction force exerted on the collar we are using the formula,

\frac{1}{2} k(x^2_f - x^2_i ) + F\times y + \frac{1}{2} m v^{2} _{c}  = mgy

Here we are given,

k = The spring has a spring constant.

= 25.5 N/m.

x_f = Final length of the spring .

= \sqrt{1.25^2+1.8^2}  -0.60

= 1.591 m

x_i= The initial length of the spring.

= 1.25−0.60

=0.65 m

y=The collar then travels downward a distance.

=  1.80 m.

m= The mass of the collar.

=3.55 kg

v_c = the velocity of the collar.

= 3.39 m/s.

g = The acceleration due to gravity.

= 9.81 m/s²

We have to calculate the magnitude of the average friction force exerted on the collar = F

Now we put the known values in the above equation, we get;

\frac{1}{2} k(x^2_f - x^2_i ) + F\times y + \frac{1}{2} m v^{2} _{c}  = mgy

Or, \frac{1}{2} \times 25.5 \times((1.591)^2 - (0.65)^2 ) + F\times 1.80 + \frac{1}{2}\times 3.55\times (3.39)^{2}  = 3.55\times 9.81\times 1.80

Or, F= 8.641 N

From the above calculation we can conclude that,

The magnitude of the average friction force exerted on the collar (F)=  8.641 N

Learn more about friction:

brainly.com/question/24338873

#SPJ4

Disclaimer: This question is incomplete in the portal. Here is the complete question.

Question:

The 3.55 kg collar shown below is attached to a spring and released from rest at A. The collar then travels downward a distance of y = 1.80 m. The spring has a spring constant of k = 25.5 N/m. The distance a is given as 1.25 m. The datum for gravitational potential energy is set at the horizontal line through A and B. Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at c is 3.39 m/s and the spring has an unstretched length of 0.60 m .

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Dmitrij [34]
The speed of bullet =
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Answer:

Explanation:

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Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

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