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defon
3 years ago
5

Do the proton and the neutron have exactly the same mass? How do the masses of the proton and the neutron compare to the mass of

the electron? Which particles make the greatest contribution to the mass of an atom? Which particles make the greatest contribution to the chemical properties of an atom?
Physics
1 answer:
True [87]3 years ago
6 0

Answer:

Explanation:

mas of proton = 1.673 x 10^-27 kg

mass of neutron = 1.675 x 10^-27 kg

mass of electron = 9.1 x 10^-31 kg

(a) the mass of proton and the mass of neutron is not exactly same.

(b) mass of proton = 1838.46 x mass of electron

mass of neutron = 1840.65 x mass of electron

(c) As proton and neutrons are more massive than the electrons, so the protons and the neutrons has the greatest contribution of mass of an atom.

(d) The greatest contribution to the chemical properties of an atom is due to the electrons.

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Forms of energy! Write a brief summary about each form of energy below.
stepan [7]

Answer:

Hope this helps!! :D

Explanation:

Mechanical energy is power that an object gets from its position and motion. the energy released during nuclear fission or fusion, typically to make electricity.

Thermal energy is the energy given off by hot things like fire.

Chemical energy is energy stored in the bonds of chemical compounds.

Electromagnetic energy is a form of energy that is reflected or emitted from objects in the form of electrical and magnetic waves that can travel.

Electrical energy is energy derived from electric potential energy or kinetic energy.

Nuclear energy is the energy released during nuclear fission or fusion, typically used to generate electricity.

4 0
3 years ago
Runs 4 m North and then runs 9 m West. Calculate Distance and Displacement.
mixas84 [53]

Answer:

Take north as y and west as -x.

distance=√(x^2+y^2)

displacement= tan theta(tan^-1) (y/x)

answers should be, (9.85m, 66.04°)

8 0
3 years ago
A worker at the top of a 588-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligib
liq [111]

The final velocity of the tool is 107.4 m/s

Explanation:

We can solve this problem by using the principle of conservation of energy.

In fact, if air resistance is negligible, the total mechanical energy of the tool is conserved during the fall, so we can write:

K_i + U_i = K_f + U_f

where

K_i = 0 is the kinetic energy of the tool at the top (zero since it is at rest)

U_i = mgh is the gravitational potential energy of the tool at the top, where

m is the mass of the tool

g is the acceleration of gravity

h is the heigth of the tool

K_f = \frac{1}{2}mv^2 is the kinetic energy of the tool just before hitting the ground, where

v is the final speed of the tool

U_f = 0 is the gravitational potential energy of the tool at the bottom (zero since the height is zero)

Re-arranging the equation,

mgh=\frac{1}{2}mv^2

where we have

g=9.8 m/s^2\\h=588 m

And solving for v,

v=\sqrt{2gh}=\sqrt{2(9.8)(588)}=107.4 m/s

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0
3 years ago
A theory was not originally a hypothesis. true or false?
Anna11 [10]
The answer is false. many famouse scientist used the very scientific theory that we use today
3 0
3 years ago
Calculate the angular velocity of the earth in its orbit around the sun.
Orlov [11]

Answer:

0.0172rad/day=1.99x10^{-7}rad/second

Explanation:

The definition of angular velocity is as follows:

\omega=2\pi f

where \omega is the angular velocity, and f is the frequency.

Frequency can also be represented as:

f=\frac{1}{T}

where T is the period, (the time it takes to conclude a cycle)

with this, the angular velocity is:

\omega=\frac{2\pi}{T}

The period T of rotation around the sun 365 days, thus, the angular velocity:

\omega=\frac{2\pi}{365days}=0.0172rad/day

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:

Firt conveting to hous

365days(\frac{24hours}{1day} )=8760hours

then to minutes

8760hours(\frac{60minutes}{1hour} )=525,600minutes

and finally to seconds

525,600minutes(\frac{60seconds}{1minute})=31,536x10^3seconds

thus, angular velocity in rad/second is:

\omega=\frac{2\pi}{31,536x10^3seconds}=1.99x10^{-7}rad/second

3 0
3 years ago
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