Answer:
Amplitude = 0.058m
Frequency = 6.25Hz
Explanation:
Given
Amplitude (A) = 8.26 x 10-2 m
Frequency (f) = 4.42Hz
Conversation of energy before split
½mv² = ½KA²
Make A the subject of formula
A =  
 
Conversation of energy after split
½(m/2)V'² = ½(m/2)V² = ½KA'²
½(m/2)V² = ½KA'²
Make A the subject of formula
First divide both sides by ½
(m/2)V² = KA'²
Divide both sides by K
 V² = A'²
V² = A'²
 = A'
 = A'
Substitute  for A in the above equation
 for A in the above equation
A' = A/√2
A' = 8.26 x 10^-2/√2
A' = 0.05840702012600882
Amplitude after split = 0.058 (Approximated)
Frequency (f') = f√2
f' = 4.42√2
f' = 6.25082394568908011
Frequency after split = 6.25Hz (approximated)
 
        
             
        
        
        
Explanation:
 Given formula: 
             ME= mv²+mgh
mv²+mgh
   To make height the subject of the formula, follow the following procedures;
      Subtract  mv² from both side of equation
mv² from both side of equation 
  M.E -  mv² =
mv² =  mv² -
mv² -  mv²+mgh
mv²+mgh
                   This gives: 
                         M.E -  mv² = mgh
mv² = mgh
Multiply both sides of the expression by 
   ( M.E -   mv² ) x
mv² ) x   =
 =   x mgh
 x mgh
        h = ( M.E -   mv² ) x
mv² ) x  
Learn more: 
Kinetic energy brainly.com/question/6536722
#learnwithBrainly
 
        
             
        
        
        
Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?
 
        
                    
             
        
        
        
Explanation:
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