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2 years ago

An external computer flash drive can hold 1 gigabyte of data. How many bytes is this?

Physics

2 answers:

Fed [463]2 years ago

7 0

Answer: 1 gigabyte of a computer drive can hold of about $10^9$ bytes.

Explanation: We are given an external computer flash drive which can hold a data of about 1 gigabyte.

We know that,

1 gigabyte contains 1000 Megabytes of data

and 1 megabyte of a data can hold of about 1 million bytes.

From the above conversion, we get

$1GB=(1000\times 10^6)bytes=10^9bytes$

LenKa [72]2 years ago

6 0

"gig..." means a billion of something, or 10^9. In binary hardware, it's actually 1,073,741,824 bytes. That's 2^30.

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Without completing the calculations, determine what the new volume will be in the problem below. Also, explain how you were able

Talja [164]

Boyles law

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Double the pressure equals 1/2 of original volume, assuming temperature remains the same.

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3 years ago

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skad [1K]

Answer:

Explanation:

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3 years ago

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mamaluj [8]

Answer:Draw a T-s diagram for the ideal Rankine Cycle

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2 years ago

What number is between 2000 and 2500

Kitty [74]

If its just a number 2,300 is an answer

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3 years ago

3. A coil of 100 turns encloses an area of 100 cm2. It is placed at an angle of 700 with a

sasho [114]

Explanation:

Given that,

Number of turns in the coil, N = 100

Area of the coil, A = 100 cm² = 0.01 m²

It is placed at an angle of 70°.

Magnetic field, B = 0.1 Wb/m²

We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.

Magnetic flux is given by :

$\phi =BA\cos\theta\\\\\text{For N turns},\\\phi =NBA\cos\theta \\\\\phi=100\times 0.1\times 0.01\times \cos(70)\\\\=0.034\ Wb$

So, the magnetic flux through the coil is 0.1 Wb.

Emf induced in the coil is :

$\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{0.034}{10^{-3}}\\\\=34\ V$

So, 34V of emf is induced in the coil.

7 0

2 years ago