Answer:
5.865 μs
Explanation:
t₀ = Time taken to decay a muon = 2.20 μs
c = Speed of Light in vacuum = 3×10⁸ m/s
v = Velocity of muon = 0.927 c
t = Lifetime observed
Time dilation

∴Lifetime observed for muons approaching at 0.927 the speed of light is 5.865 μs
Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
The object's speed will remain constant after the it leaves his hand.
So will HIS speed in the opposite direction.
The correct formula to use is: F = G [M1*M2] /r^2
Where,
G = the force of gravity
M1 = the mass of the first object [the mass of the astronaut]
M2 = the mass of the second object [the mass of the planet]
r = the distance between the two objects in metre
F = 6.67 * 10^-11 [66.5 * 8.43 * 10^23] / [4.40 * 10^6]^2
F = 193N.<span />
Sc (21) , Y (39) , La (57) , Ce (58) , Pr (59) , Nd (60) , Pm (61) , Sm (62) , Eu (63) , Gd (64) , Tb (65) , etc (hoped that helped)