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noname [10]
3 years ago
13

Which of these molecules has a lewis structure with a central atom having no nonbonding electron pairs?

Chemistry
1 answer:
earnstyle [38]3 years ago
4 0
Methane is one CH4 with all sides of carbon being bonded with hydrogen atoms
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A chemist wants to make 6.5 L of a 0.340 M CaCl2 solution. Part A What mass of CaCl2 (in g) should the chemist use? Express your
katovenus [111]

Answer:

The answer to your question is 245 grams

Explanation:

Data

Volume 6.5 L

Molarity = 0.34

mass of CaCl₂ = ?

Process

1.- Calculate the molar mass of CaCl₂

molar mass = (1 x 40) + (2 x 35.5)

                   = 40 + 71

                   = 111 g

2.- Convert the grams to moles

                       111 g of CaCl₂ -------------- 1 mol

                         x                   ---------------0.34 mol

                         x = (0.34 x 111) / 1

                         x = 37.74 g

3.- Calculate the total mass

                        37.74 g ------------------ 1 L

                            x        ------------------ 6.5 L

                            x = (6.5 x 37.74) / 1

                            x = 245.31

3 0
3 years ago
Ions of an element (elements with different charges) contain different numbers of what
Vadim26 [7]

Answer:

an ion is an element that has different numbers of protons and electrons

Explanation:

An ion is positive when it has more protons than electrons and negative when it has more electrons than ions.

(Hope this was helpful!) :)

7 0
3 years ago
Directions are in the picture
Mrrafil [7]

Answer:

Question Clear

Explanation:

Make sure your question is clear.

6 0
3 years ago
Explain how to calculate net force.
Alisiya [41]
Force acting on the body when the body is at rest the net formals is given
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3 years ago
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
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