Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
= 
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹
<u>Statement</u><u>:</u>
A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.
<u>To </u><u>find </u><u>out</u><u>:</u>
The force required to accelerate the ball.
<u>Solution</u><u>:</u>
- Mass of the ball (m) = 600 g = 0.6 Kg
- Initial velocity (u) = 0 m/s [it was at rest]
- Final velocity (v) = 14 m/s
- Time (t) = 0.1 s
- Let the acceleration be a.
- We know the equation of motion,
- v = u + at
- Therefore, putting the values in the above formula, we get
- 14 m/s = 0 m/s + a × 0.1 s
- or, 14 m/s ÷ 0.1 s = a
- or, a = 140 m/s²
- Let the force be F.
- We know, the formula : F = ma
- Putting the values in the above formula, we get
- F = 0.6 Kg × 140 m/s²
- or, F = 84 N
<u>Answer</u><u>:</u>
The force required to accelerate the ball is 84 N and this force acts along the direction of motion.
Hope you could understand.
If you have any query, feel free to ask.
Answer:
a) v = 13.8 m / s
, b) a = 95.49 m / s²
, c) a force that goes to the center of the carnival ride and d) μ = 0.10
Explanation:
For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics
a) reduce the magnitudes to the SI system
w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s
The equation that relates linear and angular velocity is
v = w r
v = 6.91 2
v = 13.8 m / s
b) centripetal acceleration is given by
a = v² / r = w² r
a = 6.91² 2
a = 95.49 m / s²
c) this acceleration is produced by a force that goes to the center of the carnival ride
d) Here we use Newton's second law
fr -W = 0
fr = W
μ N = mg
Radial shaft
N = m a
N = m w² r
μ m w² r = m g
μ = g / w² r
μ = 9.8 / 6.91² 2
μ = 0.10
Answer:
K = 202.5 J
Explanation:
Given that,
Mass of pie is 5 kg
Velocity of pie is 9 m/s
We need to find the kinetic energy of a pie. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :

So, the kinetic energy of the pie is 202.5 J.