Answer:
p = mv
Explanation:
- The momentum of a body is defined as the product of its mass and velocity. Its physical symbol is 'p'.
- The formula for momentum is given by
p = mv
Where,
m - the mass of the body in kg
v - velocity of the body in m/s
- Therefore, the unit of momentum is expressed as the kg m/s
- The momentum of a body is always associated with its motion. It is a vector quantity and it is directed in the direction of the velocity vector.
- If a body is at rest, the momentum associated with the body is zero.
- The momentum plays a significant role in the kinematics of the body. As similar to the energy conservation law, the total momentum of the body is conserved.
Answer:
90 meters.
Explanation:
The correct answer is: B.) 90 m
Answer:
Explanation:
Impedence of the circuit = peak voltage / peak current
= 5.8 / 51 x 10⁻³
= 113.725 ohm.
1 / wC =113.725
w = 1 / (113.725 x 22 x 10⁻⁹ )
= 10⁹ / 2.5 x 10³
=10⁶ / 2.5
40 x 10⁴
frequency n = 40 x 10⁴ / 2 x 3.14
6.37 x 10⁴ Hz.
b ) charge on the capacitor = 1 C
V = Q / C
= Charge / capacitor
= 1 / 22 x 10⁻⁹
4.54 x 10⁷ V.
The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:
ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)
or equivalently,

(see the attached graphic)
We have
- ducks (relative to wind) = 7.0 m/s in some direction <em>θ</em> relative to the positive horizontal direction, or

- wind (relative to Earth) = 5.0 m/s due East, or

- ducks (relative to earth) = some speed <em>v</em> due South, or

Then by setting components equal, we have


We only care about the direction for this question, which we get from the first equation:



or approximately 136º or 224º.
Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies <em>both</em> equations. We want

which means <em>θ</em> must be between 180º and 360º (since angles in this range have negative sine).
So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.
<h2>
Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s</h2>
Explanation:
In horizontal direction there is acceleration or deceleration for a ball tossed upward at an initial angle of 43° off the ground.
So the horizontal component of velocity always remains the same.
Horizontal component of velocity is the cosine component of velocity.
Initial velocity, u = 10 m/s
Angle, θ = 43°
Horizontal component of velocity = u cosθ
Horizontal component of velocity = 10 cos43
Horizontal component of velocity = 7.31 m/s
Since the horizontal velocity is unaffected, we have
Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s