The molarity of the solution is calculated by dividing the number of moles of the solute, in moles, by the total volume of the solution, in liters.
The molar mass of calcium hydroxide, Ca(OH)2 is calculated below.
m = molar mass Ca + 2(molar mass O) + 2(molar mass H)
Substituting,
m = 40 g/mol + 2(16 g/mol) + 2(1 g/mol)
m = 74 g/mol
To get the number of moles Ca(OH)2 in 75.8 grams,
n = (75.8 grams)(1 / 74 g/mol) = 1.024 moles
The molarity, M, is therefore,
M = (1.024 moles Ca(OH)2) / (1.2 L)
M = 0.854 M
<em>Answer: 0.854 M</em>
Answer:
aa. Which sample(s) is classified as a compound? How do you know?
Answer:
400°C
Explanation:
22,000 cal / (0.11 cal/g°C x 500 g) = 400°C
