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4 years ago

Sodium electron configuration

Chemistry

1 answer:

Helen [10]4 years ago

8 0

Answer: [Ne] 3s¹ sodium electron configuration

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What type of ion do elements from each of the following groups form ,<br> group1 <br> group 7.

Artemon [7]

Answer:

group 1 - cations charge +1

group 7 - anions charge -1

Explanation:

Group 1 has one valence electron and will lose one electron to complete the octet.

Group 7 has 7 valence electrons and will accept an electron to complete the octet.

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3 years ago

2KCIO3 ----------> 2KCI + 302<br> How many moles of KCIO3 are needed to make 3.5 moles of KCL?

lyudmila [28]

Answer:

3.5 mol KClO3

Explanation:

Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.

x mole of KClO3 = 3.5 mol KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3

x mole of KClO3 = 3.5 mol KClO3

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3 years ago

Which of these salts has the highest pH? K2SO4 Cu2SO4 NH4Cl NaCH3COO

OLEGan [10]

the answer is D. just took the test

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4 years ago

Read 2 more answers

What is chemistry the study of?

IRINA_888 [86]

Chemistry is the study of substances—that is, elements and compounds.

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3 years ago

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A geochemist measures the concentration of salt dissolved in Lake Parsons and finds a concentration of 21.0 gL⁻¹. The geochemist

dedylja [7]

Answer:

The percentage of Lake Parsons which has evaporated since it became isolated is 68.24%.

Explanation:

The concentration of salt dissolved in Lake Parson = 21.0 g/L

= In 1 L of lake Parson water = 21.0 g of salt

The concentration of salt in several nearby non-isolated lakes = 6.67 g/L

The salt concentration in Lake Parsons before it became isolated = 6.67 g/L

In 1 L of lake water = 6.67 g of salt

If 1 L of lake Parson water has 6.67 g of salt. Then 21.0 grams of salt will be in ;

$\frac{1}{6.67}\times 21.0 L = 3.15 L$

Water evaporated = 3.15 L - 1 L = 2.15 L

The percentage of Lake Parsons which has evaporated since it became isolated:

$\frac{2.15 L}{3.15 L}\times 100=68.25\%$

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4 years ago