Formula for velocity:
V(t) = Vi + at
Where V(t) is velocity at time t, Vi is initital velocity, and a is acceleration.
Solving for a:
V(8) = Vi + a(8)
V(8) = 0 (car has stopped)
0 = 24 + 8a
-24 = 8a
a = -3 m/s/s
You have two possible ways to connect the springs: in parallel or in series.
The equivalent stiffness of three springs in parallel is given by:
k_eq = k₁ + k₂ + k₃
In order to keep this number the smallest possible, you need to take the three springs with smaller k:
k_eq_min = 3.5 + 6 + 8.5 = 18 N/m
The equivalent stiffness of three springs in series is given by:
1 / k_eq = 1 / <span>k₁ + 1 / k₂ + 1 / k₃
In order to get the smallest k_eq possible, 1 / k_eq must be the biggest possible, therefore you need to take again the three springs with smaller k:
k_eq = 1 / (</span>1 / <span>k₁ + 1 / k₂ + 1 / k₃)
= 1 / (1 / 3.5 + 1 / 6 + 1 / 8.5)
= 1.754 N/m
Therefore, in order to get the smallest equivalent stiffness, you need to connect the first three springs in series (one after the other).</span>
Answer:
Explanation:
current I = 14 x 10⁻³ A
distance of current d = 2.2 x 10⁻² m
Magnetic field B due to a long straight current carrying wire
B = (μ₀ /4π) x (2 I / d )
= 10⁻⁷ x 2 x 14 x 10⁻³ / 2.2 x 10⁻²
= 12.72 x 10⁻⁸ T .
To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:
= Coulomb's constant
q = Charge
r = Radius
At the same time
The values of variables are the same, then if we replace in a single equation we have this expression,
If we replace the values, we have finally that the charge is,
Therefore the potential energy of the system is