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3 years ago

Which of these is an example of interactions between the atmosphere and biosphere?

Physics

2 answers:

Alex17521 [72]3 years ago

8 0

Answer: d. uprooting of trees during tornadoes.

Explanation:

An atmosphere can be define as the mass of gases collectively called as air. It covers the earth and protects it from the direct incident rays coming from the sun which can cause damage to the living beings.

An biosphere is the important sphere of the earth which consists of living beings.

A tornado is a natural disaster which is a strong wind storm. It consists of strong column of air that spins very fast and causes a lot of damage to the material which comes in it's direct contact.

Uprooting of trees during tornado is the correct option because of the fact that tornado initially develop in the atmosphere and it effects the biosphere. The tree is the part of the biosphere.

SashulF [63]3 years ago

6 0

It might be D, Tornadoes deal with atmosphere affecting trees in the biosphere

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Un móvil se encuentra en la posición inicial x0 = 22 m, y se mueve con velocidad 5 m/s. Calcula la posición en la que se encuent

Brilliant_brown [7]

Answer:

La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.

Explanation:

El movimiento rectilíneo uniforme (MRU) es el movimiento que describe un cuerpo o partícula a través de una línea recta a velocidad constante.

La distancia recorrida, x , por un móvil que tiene un MRU con un velocidad v durante el intervalo de tiempo t es:

x= x0 + v*t

donde x0 es la posición inicial.

En este caso:

x0= 22 m
v= 5 m/s
t= 30 s

Reemplazando:

x= 22 m + 5 m/s* 30 s

Resolviendo:

x= 22 m + 150 m

x= 172 m

<u><em>La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.</em></u>

8 0

3 years ago

The gravitational force strength on the moon is 1.63N/Kg if the rock on the moon weighs 200N how much does the same rock weigh o

FromTheMoon [43]

m = Q(on moon) * G(on moon) = 200N * 1.63N/kg = 326kg

Q(Earth)= g * m = 10m/s2 * 326kg = 3260N

8 0

3 years ago

How deep can an object with 6360N hitting on a sponge get ???

borishaifa [10]

Answer:

The sponge must go $\dfrac{636}{m}\ \text{meter}$ deep

Explanation:

If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.

We know that, F = mgh

m is mass

g is acceleration due to gravity

$h=\dfrac{F}{mg}\\\\h=\dfrac{6360}{10m}\\\\h=\dfrac{636}{m}\ \text{meter}$

So, the sponge must go $\dfrac{636}{m}\ \text{meter}$ deep.

5 0

4 years ago

Name two laboratory equipment in the picture . b ) Identify two mistakes that these people in the laboratory above are doing

pishuonlain [190]

The two laboratory equipment in the picture are beaker and chemicals.The people in the picture are not wearing any protective gears while (a) working in the laboratory (b) Throwing the chemicals on the floor.

Among the many items that would be considered general lab equipment are pipettes, scales, centrifuges, Bunsen burners, freezers, hot plates, incubators, coolers, stirrers, water baths, and fume hoods

The dangers of working in a laboratory setting include:

Chemical hazards: Handling toxic substances can cause irritation and carcinogenicity.

Biological hazards: Biological hazards include hazards from working with small animals, working with blood borne pathogens and working with biological agents, such as viruses and bacteria.

Physical hazards: Physical hazards include exposure to noise, poor posture and the explosibility and flammability of substances.

Safety hazards: Safety hazards include unbalanced centrifuges, danger when handling hot sterilized items and electrical hazards, such as shock, explosions, blasts and electrocutions.

Allergy hazards: A common allergy hazard in the laboratory setting is a latex allergy, as many of the materials used in a laboratory setting are latex.

Learn more about Laboratory experiments at brainly.com/question/8430576

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3 0

1 year ago

A block of mass 0.510 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T

maria [59]

Answer:

x=0.46m, speed=7.9m/s

Explanation:

Using the concept of conservation of energy:

1. kinetic energy of mass m and velocity v: $E_k=\frac{1}{2}mv^2$