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3 years ago

6

Which best explains what will happen if Sharilyn unscrews a bolt with a short handled wrench?

2 answers:

bezimeni [28]3 years ago

8 0

The last choice is the correct one. This is the reason that wrenches
have long handles.

If the bolt is really stuck or rusted on there, a person who is careful
and knows what he's doing will sometimes put one end of a 2-ft pipe
over the wrench-handle, and then push on the other end of the pipe.
Pushing on a point that's farther away from the bolt always makes it
easier to unscrew.

zepelin [54]3 years ago

8 0

The correct answer is D)

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What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?

xeze [42]

The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

<h3>Change in energy level of the electron</h3>

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

ΔE = Eb - Ef

ΔE = -2.68 eV - (-5.74 eV)

ΔE = 3.06 eV

Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

Learn more about energy level here: brainly.com/question/14287666

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1 year ago

Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal dis

Stella [2.4K]

Answer:

$v_x = 4.87 m/s$

Explanation:

Height of the cliff is given as

$h = 37.1 m$

now the time taken by the diver to hit the surface is given as

$h = \frac{1}{2}gt^2$

$37.1 = \frac{1}{2}(9.8)t^2$

$t = 2.75 s$

Now in the same time it has to cover a distance of 13.39 m

so the speed in horizontal direction is given as

$v_x = \frac{x}{t}$

$v_x = \frac{13.39}{2.75}$

$v_x = 4.87 m/s$

3 0

3 years ago

The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in

N76 [4]

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

$d=\frac{v^2}{g}sin 2\theta$

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

$\theta$ is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

$\theta=45^{\circ}$ is the angle

Solving for v, we find the speed of the projectile:

$v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s$

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adelina 88 [10]

Compression is the correct answer

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3 years ago

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