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Rama09 [41]
3 years ago
5

What are the types of radiation

Physics
2 answers:
Leno4ka [110]3 years ago
8 0

Answer: The types of radiation are: alpha radiation, beta radiation, gamma radiation, and x radiation. Neutron radiation is also encountered in nuclear power plants

Explanation:

arlik [135]3 years ago
4 0

Answer:

solar

Explanation:

the one from the sun.

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When you walk across the ground and push on it with your feet...
DerKrebs [107]

Answer:

The ground pushes back on your feet with equal force

Explanation:

When you walk across the ground and push on it with your feet, the ground pushes back on your feet with an equal and opposite force.

This interpretation and knowledge is gotten from Newton's third law of motion.

It states that "action and reaction force are equal and opposite in nature".

  • The force applied to a body responds with an opposite force in the other direction.
  • Therefore, the reaction force is of equal magnitude but directed in another direction.
4 0
3 years ago
Read 2 more answers
Why is carbon added to iron
swat32

Answer:

it transforms it into high carbon alloy that is harder and can be sharper but is also more brittle in the process.

Explanation:

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3 years ago
Identify the forces acting on motor vehicle in straight line motion on a horizontal surface
tigry1 [53]

Friction, engine thrust, normal reaction and weight, these are the forces acting on motor when it moves in a straight line

7 0
3 years ago
A neutron at rest decays (breaks up) to a proton and an electron. Energy is released in the decay and appears as kinetic energy
SashulF [63]

Answer:

5.444\times 10^{-4}

Explanation:

The momentum of the neutron before and after the decay  is the same since there's no external force.

P_{sys}=const\\\\P=mv\\\\K=0.5mv^2

#The neutron is initially at rest, so after the decay:

P_A+P_B=0\\\\P_A=-P_B

#After decay, the proton has +ve direction  with a velocity v_Awhile the electron moves in a negative direction with a velocity v_B

Therefore:

P_A=m_Av_A, P_B=m_Bv_B\\\\\therefore m_Av_A,=m_Bv_B

Let the energy released during the decay be Q:

Q=K_{tot}=K_A+K_B\\\\Q=K_A+0.5m_Bv_B^2\\\\Q=K_A+0.5m_B(\frac{m_A}{m_B})^2v_A^2\\\\\ But \ K_A=0.5m_Av_A^2\\\\\therefore Q=K_A+\frac{m_A}{m_B}K_A=K_A(1+\frac{m_A}{m_B})\\\\=Q=\frac{m_A+m_B}{m_B}K_A\\\\m_A=1836m_B\\\\\frac{K_A}{Q}=\frac{m_B}{1836m_B+m_B}=\frac{1}{1837}\\\\\frac{K_A}{Q}=5.444\times10^{-4}

Hence,Kp/Ktot is 5.444x10^(-4)

4 1
3 years ago
COVA hahtyimghhjlouvr​
Kryger [21]

Answer:

heyyy

Explanation:

what's poppin

6 0
3 years ago
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