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liubo4ka [24]
3 years ago
11

Block and tackle is used only in crain why​

Physics
2 answers:
SpyIntel [72]3 years ago
8 0
What they said said ^^^^
son4ous [18]3 years ago
7 0
A block and tackle or only tackle is a system of two or more pulleys with a rope or cable threaded between them, usually used to lift heavy loads.
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A magnetic pickup is used to detect the shaft speed of an experimental high speed compressor. a gear with 12 teeth is used to ex
worty [1.4K]
The answer would be 39 seconds
5 0
3 years ago
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Density of water is 1000 kg/m^3. What will be the volume of 35000 kg water?
d1i1m1o1n [39]
Volume = mass/density
Volume = 35000/1000
Volume = 35m^3
8 0
2 years ago
Ls -2 a solution of 4x +3= -5?.<br>​
torisob [31]

Answer:

yes

Explanation:

Let's solve your equation step-by-step.

4x+3=−5

Step 1: Subtract 3 from both sides.

4x+3−3=−5−3

4x=−8

Step 2: Divide both sides by 4.

4x  / 4  =  −8  / 4

x=−2

Hope it helps,

Please mark me as the brainliest

Thank you

5 0
3 years ago
A firecracker in a coconut blows the coconut into three pieces. Twopieces of equal mass fly off south and west, perpendicular to
loris [4]

Answer:

V = 13m/s

North-East (i.e. 45 degree from North)

Explanation:

This question deals with the idea of momentum.

Since the directions of a compass are fixed, we can take south as horizontal and west as vertical. Since both pieces of coconut are of equal mass, then the resultant of the two pieces would be in between South and West and the third piece would be opposite this direction and be in the North-East (i.e. 45 degree from North) direction

To find the speed of the third piece, we first find the speed on the two pieces of the coconut in terms of V_{x} (horizontal component of velocity) and V_{y} (vertical component of velocity)

We have

V_{y} = Velocity in South direction = 18m/s

m_{y} = Mass of piece in South direction = m

V_{x} = Velocity in West direction = 18m/s

m_{x} = Mass of piece in West direction = m

V_{ry} = Velocity of Third Piece in North direction = unknown

V_{rx} = Velocity of Third Piece in East direction = unknown

m = Mass of third piece = 2m

mV_{ry}  = m_{y} V_{y} \\ 2mV_{ry}  = m18\\ V_{ry} = 9

mV_{rx}  = m_{x} V_{x} \\ 2mV_{rx}  = m18\\ V_{rx} = 9

Since we now know the horizontal and vertical component of the velocity of the third piece of coconut we find the resultant velocity. Since we know the direction is North-East, we can imagine a right angled triangle with base of 9 and height 9 and the hypotenuse equal to the resultant velocity .

We can simply apply the Pythagoras theorem and find the hypotenuse

Hypotenuse^{2}  = Height^{2}  + Base^{2} \\ V_{3}^2  = 9^{2} + 9^{2} \\ V = 12.728 m/s

V = 13m/s

6 0
3 years ago
A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca
viva [34]

Answer:

a=0.2*10^{-5}g

Explanation:

From the question we are told that:

Mass M=180=>0.18kg

Charge Q=18mC=18*10^-^3C

Velocity v=2.2m/s

Length of Wire L=8.6cm=>0.086

Current I=30A

Generally the equation for Magnetic Field of Wire B is mathematically given by

 B=\frac{\mu_0*I}{2\pi*l}

 B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}

 B=6.978*10^{-5}T

Generally the equation for Force on the plane F is mathematically given by

 F=qvB

Therefore

 ma=qvB

 a=\frac{qvB}{m}

 a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}

 a=2.37*10^{-5}

Therefore in Terms of g's

 a=\frac{2.37*10^{-5}}{9.8}

 a=0.2*10^{-5}g

8 0
2 years ago
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