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siniylev [52]
3 years ago
12

How does the electric force between two charged particles change if the

Physics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

increased by a factor of 4

Explanation:

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It takes a student 12.0 minutes to get home from school while riding their bike at 6.7 m/s.
givi [52]

Answer: 289.44km

Explanation:

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4 years ago
What happens when a blaring siren moves away from you
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It gets quieter as the sound waves have to travel further and so the volume decreases
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4 years ago
The number of times a machine multiplies the effort force is?
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Mechanical advantage is a force which is measure of a force amplifying effectiveness of a simple machine.so t<span>he number of times a machine multiplies the effort force is mechanical advantage .
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4 0
3 years ago
A weight lifter lifts a 1.0 x 103 N weight 1.5 m in 2.0 s. The power is?
viktelen [127]

Answer:

750W

Explanation:

Given parameters:

Weight = 1 x 10³N = 1000N

Distance  = 1.5m

Time  = 2s

Unknown:

Power = ?

Solution:

Power is the rate at which work is done

  Work is the force applied on a body to move it through a particular distance

         Work = force x distance

            Power = \frac{work}{time}

Now, work = 1000 x 1.5 = 1500J

So;

     Power  = \frac{1500}{2}   = 750W

5 0
3 years ago
A loop of current-carrying wire has a magnetic dipole moment of 5. 0 10–4 am2. if the dipole moment makes an angle of 57° with a
Digiron [165]

The potential energy will be 1.46*10^-4J.

To find the answer, we have to know about the torque acting on a current loop in a uniform magnetic field.

<h3>How to find the potential energy of the loop?</h3>
  • We have the expression for torque acting on a current loop in a uniform magnetic field as,

                         \tau=MBsin\theta

where; M is the magnetic dipole moment, B is the magnetic field , and theta is the angle between M and B.

  • As we know that, the torque is equal to force times the perpendicular distance. Thus, it is equivalent to the work done. This work is stored as the potential energy in the loop.
  • Thus, the potential energy will be,

            \tau=W=U=MBsin\theta=5*10^{-4}*0.35*sin57=1.46*10^{-4}J

Thus, we can conclude that, the potential energy will be 1.46*10^-4J.

Learn more about the torque here:

brainly.com/question/27949876

#SPJ4

7 0
2 years ago
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