Answer: False
Explanation: The chemical hazard label indicates the class of harzard of chemical products. It appears on their Safety Data Sheet (SDS), which contains a lot of informations about these substances.
The chemical hazard label is divided into four colors and which one has a meaning (categorie) connected with a number, like:
Blue: Health hazard - If the chemical is deadly (4), extreme danger (3), hazardous (2), slightly hazardous (1) or a normal material (0).
Red: Fire hazard (flammability) - If the chemical has flash point bellow 73ºF (4), bellow 100ºF (3), above 100ºF not exceeding 200ºF (2), above 200ºF (1) or will not burn (0).
Yellow: Reactivity (it can be related to instability) - If the chemical may detonate (4), shock and heat may detonete it (3), if it can suffer a violent chemical change (2) or unstable if heated (1) or if it is stable (0).
White: Specific hazard - If the chemical is acid (ACID) or alkali (ALK), for example.
Answer:
28 g solute per 100 g of solution
Explanation:
28% mass means that in all your solution you have 28% of your solute, you could use grames/grames, ml/ml or whatever you want to. So if you are working with a 100 grams solution, 28 grams of that solution must be solute if you want a 28% mass. So, the correct answer is 28 g solute per 100 g of solution.
The answer would be: C. 160.3 J/mol*K
To solve this question, you need to know the equation for Gibbs free energy formula. Entropy is expressed as delta S. The temperature would be expressed as T. Don't forget that temperature use Kelvin as unit, not Celsius
The formula would be:
G= H- T*S
130.5 kJ/mol= 178.3kJ/mol - (25+273.15K)*S
(298.15K)*S=178.3kJ/mol - 130.5 kJ/mol
S= (47.8kJ/mol)/ 298.15K=
S= 0.1603 kJ/mol*K= 160.3 J/mol*K ------> 1kJ= 1000J
Answer:
The products are Al(NO₃)₃(aq) and H₂(g).
Al(s) + 3 HNO₃(aq) ⇒ Al(NO₃)₃(aq) + 1.5 H₂(g)
Explanation:
Let's consider the reaction between aluminum and nitric acid. This is a single replacement reaction, in which Al replaces H in HNO₃ to form aluminum nitrate. The unbalanced reaction is:
Al(s) + HNO₃(aq) ⇒ Al(NO₃)₃(aq) + H₂(g)
We start balancing N atoms by multiplying HNO₃ by 3.
Al(s) + 3 HNO₃(aq) ⇒ Al(NO₃)₃(aq) + H₂(g)
Finally, we get the balanced equation multiplying H₂ by 1.5.
Al(s) + 3 HNO₃(aq) ⇒ Al(NO₃)₃(aq) + 1.5 H₂(g)
