<span>Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
a = 2</span>√2 r
<span>Given: r = 180 pm
Therefore, a = 2</span>√2 180
<span> = 2 x 1.141 x 180
= 410.76 pm
</span><span>The length of the edge of the Ca unit cell is 410.76 pm.</span><span>
</span>
Answer:
7,01 g of indole-3-acetic acid
Explanation:
The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of <em>0,4mol / L</em>
100mL are <em>0,1L</em>. Using these values:
0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.
As the MW of the molecule is 175,2 g/mol:
0,04mol × (175,2g / mol) = <em>7,01 g of indole-3-acetic acid</em>
<em></em>
Thus, <em>you need 7,01 g of indole-3-acetic acid to generate your solution</em>.
I hope it helps!
Answer:
Cu(s) + N₂(g) + 2O₂(g) ⟶ Cu(NO₂)₂(s)
True... atoms contain what are called electrons and protons. the protons being possitively charged and the elctrons being negatively charged