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g100num [7]
3 years ago
13

The legs and the wings of an insect are attached to the ________. a. head b. thorax c. abdomen d. antennae

Chemistry
2 answers:
AveGali [126]3 years ago
7 0
<span>The legs and the wings of an insect are attached to the ________.


The correct answer is:
</span>b. thorax<span>
</span>
FrozenT [24]3 years ago
4 0
Legs and wings are attached to the thorax!
You might be interested in
What will the pressure be if 89.9 moles of argon are contained in a 12.0 L cylinder that is pressurized at a temperature of 300
irinina [24]
  • P=nRT/V
  • p=89.9(8.314)(12)/300
  • P=8969.14/300
  • P=29.89atm
  • P=29.9atm

Done!

7 0
2 years ago
15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

Best regards!

6 0
3 years ago
Determine the molarity of 1.2 mol KCl in 1.1 L of a solution?
victus00 [196]

Answer:

1.1 M

General Formulas and Concepts:

  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define variables</u>

1.2 mol KCL

1.1 L of solution

M = unknown

<u>Step 2: Solve for Molarity</u>

  1. Substitute:                    M = 1.2 mol/1.1 L
  2. Evaluate:                       M = 1.09091

<u>Step 3: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

1.09091 M ≈ 1.1 M

7 0
3 years ago
For a half-reaction in an acidic solution, which substances should you add to balance the equation?
Alla [95]
The answer is a. H+ and H2O. For a half-reaction in acidic solutions, elements that are not hydrogen and oxygen are balanced first. Then we add H2O to balance oxygen atoms and we add H+ to balance the hydrogen atoms. We do the same steps for basic solutions, but we also add hydroxide ions OH- in the latter part.
8 0
3 years ago
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