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g100num [7]
3 years ago
13

The legs and the wings of an insect are attached to the ________. a. head b. thorax c. abdomen d. antennae

Chemistry
2 answers:
AveGali [126]3 years ago
7 0
<span>The legs and the wings of an insect are attached to the ________.


The correct answer is:
</span>b. thorax<span>
</span>
FrozenT [24]3 years ago
4 0
Legs and wings are attached to the thorax!
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Which of the following is NOT an example of a chemical change?
Katyanochek1 [597]

Answer:

hi there !!

B) Water evaporates into steam.

this is correct because only physical state changes, steam can be cooled down to get water again.

4 0
3 years ago
Read 2 more answers
4. How can acids and bases behave in terms of electrolytes/reactivity?
icang [17]

Answer:

Strong acids are strong electrolytes. Such acids ionize completely.

Weak acids and bases are weak electrolytes. Such bases and acids ionize only to a small extent.

Explanation:

Electrolytes are the substances that produce ions when they are dissolved in water. Electrolytes can be categorized as bases, acids, and salts.

Strong acids are strong electrolytes. Such acids ionize completely.

Weak acids and bases are weak electrolytes. Such bases and acids ionize only to a small extent.

7 0
2 years ago
Which agent of erosion can create a limestone cave?
Ivanshal [37]
Water containing carbonic acid and calcium
5 0
3 years ago
One isotope of carbon has 6 protons and 6 neutrons. The number of protons and neutrons of a second isotope of carbon would be __
dexar [7]
D. 6 protons and 7 neutrons

As proton remains constant
6 0
3 years ago
Read 2 more answers
A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
2 years ago
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