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Helga [31]
3 years ago
9

If a cow has a mass of 9 × 10^2

Mathematics
2 answers:
kotykmax [81]3 years ago
5 0

Answer:

a) The blue whale has about 200 times more mass

Step-by-step explanation:

(blue whale mass)/(cow mass) = (1.8×10^5 kg)/(9×10^2 kg)

... = (1.8/9)×10^(5-2)

... = 0.2×10^3

... = 200

The blue whale has about 200 times as much mass as a cow.

FrozenT [24]3 years ago
4 0

Answer:

a) The blue whale has about 200 times more mass.

Step-by-step explanation:

A cow has a mass of 9 × 10^2 kilograms, and a blue whale has a mass of 1.8 × 10^5 kilograms.

The blue whale is about \frac{1.8\times10^{5}}{9\times10^{2}} times more than cow.

= \frac{180000}{900}

= 200

Hence, the answer is a) The blue whale has about 200 times more mass.

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Please Help!<br><br> Car X travels 174 miles in 3 hours.
DiKsa [7]

Answer:

The graph =

<h3>y = 58x</h3>

Step-by-step explanation:

(a)

distance covered (y) = 174 miles

time taken (x) = 3 hours

Therefore the points = (3, 174) and (0, 0) = stationary position

Find the gradient (m)

m = 174-0 / 3-0

m = 58

Therefore the equation =

<h3>y = 58x</h3>

(distance = 58 × time)

For the distance = 174 and time = 3 hours, the equation to find either distance or time = y = 58x

(b) the graph is constant, because the time and distance are also contant when the speed used is the same.

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2 years ago
Solving a right triangle ‼️ Can someone help me find A,a and c❓ (Round to the nearest tenth)
denis23 [38]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 48)° = 180° - 138° = 42°

----------------------------------------------------------

tan48° = \frac{opposite}{adjacent} = \frac{18}{a}

Multiply both sides by a

a × tan48° = 18 ( divide both sides by tan48° )

a = \frac{18}{tan48} ≈ 16.2 ( to the nearest tenth )

-----------------------------------------------------------

sin48° = \frac{opposite}{hypotenuse} = \frac{18}{c}

Multiply both sides by c

c × sin48° = 18 ( divide both sides by sin48° )

c = \frac{18}{sin48} ≈ 24.2 ( to the nearest tenth )

4 0
2 years ago
Help guys<br> I realy need help <br> I will report you if you give me the wrong answer
telo118 [61]

Answer:

the Answer is 150x + 12100 ≤ 26500

Step-by-step explanation:

The max weight is 26500 so the weight would have to be the same or less than 26500 (≤)

There is already 12100 killograms on the sipping containter so that is why you have + 12100

and you have 150x because x is the number of 150-kilogram crates

and for as many crates you have to multiply by the weight.

7 0
2 years ago
QUICK:WILL GET 20 POINTS &amp; BRAINLIEST- Compare and Contrast the incenter and the circumcenter of triangles in detail?
kvasek [131]

Answer:

A circle inscribed inside a triangle is called the incenter, and has a center called the incenter. A circled drawn outside a triangle is called a circumcircle, and it's center is called the circumcenter.

Step-by-step explanation:

4 0
2 years ago
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
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