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3 years ago

What is the highest energy orbital of elements with valence electrons in the n=3 shell?

Chemistry

1 answer:

Andrej [43]3 years ago

8 0

Answer:

d orbital

Explanation:

Given that:-

The principal quantum number, n = 3

The acceptable values of azimuthal quantum number, l are:-

l = 0 , 1 , 2

l = 0 corresponds to s orbital which can accomodate 2 electrons.

l = 1 corresponds to p orbital which can accomodate 6 electrons.

l = 2 corresponds to d orbital which can accomodate 10 electrons.

<u>Thus, the highest energy orbital is: - d orbital</u>

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White vinegar is a 5.0% by mass solution of acetic acid in water. If the density of white

Alex_Xolod [135]

The pH = 2.41

<h3>Further explanation</h3>

Given

5.0% by mass solution of acetic acid

the density of white vinegar is 1.007 g/cm3

Required

Solution

Molarity of solution :

$\tt M=\dfrac{\%mass\times \rho\times 10}{MW~acetic~acid}\\\\M=\dfrac{5\times 1.007\times 10}{60}\\\\M=0.839$

Ka for acetic acid = 1.8 x 10⁻⁵

[H⁺] for weak acid :

$\tt [H^+]=\sqrt{Ka.M}$

Input the value :

$\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.839}\\\\(H^+]=0.00388=3.88\times 10^{-3}\\\\pH=3-log~3.88=2.41$

7 0

3 years ago

Drag the item from the item bank to its corresponding match.

ozzi

Answer:

These are the elements or compounds that enter into a chemical reaction: Reactants

These are the substance(s) formed in a chemical reaction: Products

These are the reactants in the chemical equation C6H1206 +602 --> 6CO2 + 6H20: C6H1206 and 602

These are the reactants in the chemical equation 6 CO2 + 6H2O --> C6H1206 + 6 02: 6 CO2 + 6H2O

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These are the reactants in the chemical equation 2 H2O --> 2 H2 + O2: 2H2O

4 0

3 years ago

What is the percent by mass of sodium in Na2SO4? total mass of element in compound molar mass of compound Use %Element x 100

Kisachek [45]

What is the percent by mass of sodium in Na2SO4? total mass of element in compound molar mass of compound Use %Element x 100

5 0

4 years ago

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

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3 years ago

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Annette [7]

A: Now that you know how my ice be.

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3 years ago

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