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Degger [83]
3 years ago
6

Compound X has the same molecular formula as butane but has a different boiling point and melting point. What can be concluded a

bout Compound X?
Chemistry
1 answer:
Vsevolod [243]3 years ago
3 0
Compound X is an isomer of butane with different chain types. It is either straight chain or bend chain.
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What will happen if you weighed out a quantity of beans
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Answer:

When we weigh beans in this mass ratio, we must obtain the same number of beans.Explanation:

Nothing will happen

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If you produce 10 moles of oxygen gas, how many grams of water did you start with?
uysha [10]
I believe the answer is 8
5 0
4 years ago
What are all of the ways can use the atomic number to find information about an atom?
galben [10]

Answer:

The symbol for an atom can be written to show its mass number at the top, and its atomic number at the bottom. To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number: number of protons = atomic number. number of electrons = atomic number.

7 0
3 years ago
Which indicator shows whether a solution is acidic or basic, but not how strong it is?
Galina-37 [17]

Answer:

Option C

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5 0
3 years ago
Read 2 more answers
How much work is needed to assemble an atomic nucleus containing three protons (such as Be) if we model it as an equilateral tri
klio [65]

Answer:

2.16 MeV

Explanation:

To determine the amount of work done that is needed to assemble the atomic mass; we need to apply the equation;

U = \frac{3}{4 \pi E_o} (\frac{e^2}{r})

where:

\frac{1}{4 \pi E_o} = proportionality constant = (9*10^9N.m^2/C^2)

e = magnitude of the charge of each electron = (1.6*10^{-19} C)^2

r = length of each side of the vertex = (2.00*10^{-15}m)

So; replacing our values into above equation; we have:

U = 3\frac{(9*10^9N.m^2/C^2)(1.6*10^{-19} C)^2}{(2.00*10^{-15}m)}

U = 3.456 × 10 ⁻¹³ J

If we have to convert our unit from J to Mev; then we are going to have:

U = 3.456 × 10 ⁻¹³ J (\frac{1 MeV}{1.602*10^{-13}J})

U = 2.16 MeV

Therefore, the amount of work done needed to assemble an atomic nucleus =  2.16 MeV

8 0
3 years ago
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