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aleksklad [387]
3 years ago
5

Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dar

k matter. How would their rotation curves be different?(A) The orbital speeds would fall off sharply with increasing distance from the galactic center.(B) The rotation curve would be a straight, upward sloping diagonal line, like the rotation curve of a merry-go-round.(C) The orbital speeds would rise upward with increasing distance from the galactic center, rather than remaining approximately constant.(D) The rotation curve would look the same with or without the presence of dark matter.
Physics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

A) The orbital speeds would fall off sharply with increasing distance from the galactic center.

Explanation:

The plot of radial distance versus the orbital speed of objects gives us the galaxy rotation curve. The theoretical and practical curves have significant difference. A possible explanation of this difference could be the existence of dark matter.

According to the theoretical calculations the curve should increase sharply and then decrease as the radial distance increases. The theoretical graph does not take dark matter into account. But the plot made by observations shows the plot increasing first then becoming constant as the radial distance increases.

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A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the
Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

          x = 0.535 m

measured from the pivot point

measured from the far left is

           x’= 1,2 + x

           x'=  1.2 + 0.535

           x ’= 1,735 m

8 0
3 years ago
State whether the following statement are true or false .
Klio2033 [76]
1. It’s true
4 ,7 ,8 is correct
5 0
3 years ago
HELPPP IM DESPERATE
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5 0
3 years ago
12)A black body is heated from 27°C to 127° C. The ratio of their energies of radiations emitted will be
Nat2105 [25]

Answer:

81:256.

Explanation:

Let T denote the absolute temperature of this object.

Calculate the value of T before and after heating:

T(\text{before}) = 27 + 273 = 300\; \rm K.

T(\text{after}) = 127 + 273 = 400\; \rm K.

By the Stefan-Boltzmann Law, the energy that this object emits (over all frequencies) would be proportional to T^4.

Ratio between the absolute temperature of this object before and after heating:

\displaystyle \frac{T(\text{before})}{T(\text{after})} = \frac{3}{4}.

Therefore, by the Stefan-Boltzmann Law, the ratio between the energy that this object emits before and after heating would be:

\displaystyle \left(\frac{T(\text{before})}{T(\text{after})}\right)^{4} = \left(\frac{3}{4}\right)^{4} = \frac{81}{256}.

4 0
3 years ago
What is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2m/s
vlada-n [284]

Answer:

<h2>14.52 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 7.26 \times  {2}^{2}  \\  = 2 \times 7.26

We have the final answer as

<h3>14.52 J</h3>

Hope this helps you

4 0
3 years ago
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