1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksklad [387]
3 years ago
5

Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dar

k matter. How would their rotation curves be different?(A) The orbital speeds would fall off sharply with increasing distance from the galactic center.(B) The rotation curve would be a straight, upward sloping diagonal line, like the rotation curve of a merry-go-round.(C) The orbital speeds would rise upward with increasing distance from the galactic center, rather than remaining approximately constant.(D) The rotation curve would look the same with or without the presence of dark matter.
Physics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

A) The orbital speeds would fall off sharply with increasing distance from the galactic center.

Explanation:

The plot of radial distance versus the orbital speed of objects gives us the galaxy rotation curve. The theoretical and practical curves have significant difference. A possible explanation of this difference could be the existence of dark matter.

According to the theoretical calculations the curve should increase sharply and then decrease as the radial distance increases. The theoretical graph does not take dark matter into account. But the plot made by observations shows the plot increasing first then becoming constant as the radial distance increases.

You might be interested in
The element in an incandescent light bulb that releases light energy is
Leviafan [203]
A thin tungsten filament
5 0
3 years ago
A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box
vodka [1.7K]
The formula for Force is F = MA, or Force is equivalent to the product of Mass and Acceleration. 

F = 128N.
M = 35.2kg.

128 = 35.2A
Divide both sides by 35.2 to solve for the acceleration.
A = ~3.636

The acceleration is 3.636 m/s^2.

I hope this helps!
4 0
3 years ago
Read 2 more answers
A circuit contains two light bulbs connected in parallel. What would happen to the brightness of each light bulb if two more lig
laila [671]

Answer;

C. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Explanation;

-If light bulbs are connected in parallel to a voltage source, the brightness of the individual bulbs remains more-or-less constant as more and more bulbs are added to the circuit.

-The current increases as more bulbs are added to the circuit and the overall resistance decreases. In addition, if one bulb is removed from the circuit the other bulbs do not go out. Each bulb is independently linked to the voltage source

6 0
3 years ago
Read 3 more answers
Most of the countries in Europe use SI measurments. How could this be a problem if you went on a trip to Europe?
faust18 [17]
Not knowing how to convert the type of measurement according to your way of learning from where ever you come from.
5 0
3 years ago
Read 2 more answers
The distance between adjacent nodes in a standing wave pattern in a length of string is 25.0 cm:A. What is the wavelength of wav
mina [271]

A) 50 cm

B) 10000 cm/s

Explanation

Step 1

A)

If you know the distance between nodes and antinodes then use this equation:

\begin{gathered} \frac{\lambda}{2}=D \\ \text{where}\lambda\text{ is the wavelength} \\ D\text{ is the distance betw}een\text{ nodes} \end{gathered}

then, let

D=\text{ 25 cm }

now, replace to find the wavelength

\begin{gathered} \frac{\lambda}{2}=25 \\ \text{Multiply both sides by 2} \\ \frac{\lambda}{2}\cdot2=25\cdot2 \\ \lambda=50\text{ Cm} \end{gathered}

so, the wavelength is

A) 50 cm

Step 2

The speed of a wave can be found using the equation

v=\lambda f

or velocity = wavelength x frequency,

then,let

\begin{gathered} \lambda=50\text{ cm} \\ f=200\text{ Hz} \end{gathered}

replace and evaluate

\begin{gathered} v=\lambda f \\ v=50\text{ cm }\cdot200\text{ HZ} \\ v=10000\text{ }\frac{\text{cm}}{s} \end{gathered}

so

B) 10000 cm/s

I hope this helps you

6 0
1 year ago
Other questions:
  • You place a 500 g block of an unknown substance in an insulated container filled 2 kg of water. The block has an initial tempera
    12·1 answer
  • When I bump the table, the coffee in my cup spilled out. Newton's _____ law explains this reaction.
    6·2 answers
  • In a plate glass factory, sheets of glass move along a conveyor belt at a speed of 15.0 cm/s. An automatic cutting tool descends
    12·1 answer
  • A 20 kg mass is dropped from a tall rooftop and accelerates at 9.8 m/s2. What is the weight of the dropped object?
    13·2 answers
  • ANSWER ASAP PLEASE 15 POINTS
    8·1 answer
  • A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump
    10·1 answer
  • If 1.0 joule of work is required to move a charge of 1.0 coulomb between two points is an electric field the potential differenc
    13·1 answer
  • A match is being is an example of
    9·1 answer
  • g A rotating wheel requires 5.00 s to rotate 28.0 revolutions. Its angular velocity at the end of the 5.00-s interval is 96.0 ra
    11·1 answer
  • Determine the surface gravity of Earth. Its mass is 6.0 x 1024 kg and its radius is 6.4 x 106 m.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!