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svlad2 [7]
3 years ago
11

Can someone help me with this problem?

Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

no

Explanation:

u flipped it i cant see

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The best way to study young stars hidden behind interstellar dust clouds would be to use
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Answer: Infrared light

Explanation:

Infrared light is an electromagnetic radiation which has longer wavelength than visible light.

cool and faint objects are difficult to be detected using visible light.

Infrared light can pass through dust and clouds of gases. Thus, it is the best way to study the young stars hidden behind interstellar dust clouds.

8 0
3 years ago
which statement below is FALSE? A Gravity acts on any object with mass. B The closer objects are, the stronger the gravitational
GenaCL600 [577]

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Explanation:

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D<br> Question 14<br> 2 pts<br> The universe could be considered an isolated system because
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it would help if we knew the question and other answers

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5 0
3 years ago
Which kind of energy transformation occurs during skydiving? A) mechanical to gravitational B) gravitational to kinetic C) kinet
Aleks [24]

B) gravitational to kinetic

Explanation:

The skydiver, when he is located at a certain height h above the ground, possesses gravitational potential energy, equal to:

U=mgh

where m is the mass of the skydiver, g is the gravitational acceleration and h is the height above the ground. As he falls, its height h decreases, while his speed v increases, so part of the gravitational potential energy is converted into kinetic energy, which is given by

K=\frac{1}{2}mv^2

so, we see that as v increases, the kinetic energy increases. Therefore the correct answer is

B) gravitational to kinetic

7 0
4 years ago
Read 2 more answers
Part A If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 51.5 m/s in the opposite
nalin [4]

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s

Hence, this is the required solution.

7 0
4 years ago
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