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Lerok [7]
3 years ago
6

Fe(CN)63- + Re → Fe(CN)64- + ReO4--. What is reduced?

Chemistry
1 answer:
givi [52]3 years ago
6 0

Answer:

1. Fe is reduced

2. Mn is Oxidized

3. N is oxidized

Explanation:

<em>Check the image below:</em>

Reducing agent is an element or compound that loses an electron to an electron recipient in a redox chemical reaction. oxidizing agent is a substance that has the ability to oxidize other substances — in other words to accept their electrons.

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The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

Ea = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
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Leona [35]

Answer:

Yes the two of the answer is True

3 0
2 years ago
Read 2 more answers
Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the
jok3333 [9.3K]

<u>Answer:</u> The average of the densities of the given measurements is 1.363 g/mL

<u>Explanation:</u>

The equation used to calculate density of a substance is given by:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

First measured value of density, d_1 = 1.019 g/mL

Second measured value of density, d_2 = 1.498 g/mL

Third measured value of density, d_3 = 1.572 g/mL

Putting values in above equation, we get:

\rho_{mix}=\frac{d_1+d_2+d_3}{3}

\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL

Hence, the average of the densities of the given measurements is 1.363 g/mL

7 0
3 years ago
J. A gas has a volume of 12 L at 200°C with 6.0 atm.
White raven [17]

Gay Lussac's Law

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Convert:

200°C = 200 + 273 = 473 K

50°C = 50 + 273 = 323 K

Input the value:

\tt \dfrac{6}{473}=\dfrac{P_2}{323}\\\\P_2=4.097~atm

4 0
2 years ago
Read 2 more answers
Explain how condensation is invovled in the water cycle
blagie [28]

Condensation is the process of watervapor in the air is changing into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds. Condensation is also the opposite of evaporation
8 0
3 years ago
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