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ra1l [238]
3 years ago
6

5. The mass of cobalt-60 in a sample is found to have decreased from 0.800g to 0.200g in a

Chemistry
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

5.25yr

Explanation:

I think so

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The reaction is first order in cyclopropane and has a measured rate constant of k=3.36×10−5 s−1 at 720 k. if the initial cyclopr
sergey [27]

Answer:

0.0277 M.

Explanation:

The integral rate law of a first order reaction:

<em>Kt = ln ([A₀]/[A]),</em>

where, k is the rate constant of the reaction <em>(k = 3.36 × 10⁻⁵ s⁻¹)</em>,

t is the time of the reaction <em>(t = 235.0 min = 14100 s)</em>,

[A₀] is the initial concentration of cyclopropane <em>([A₀] = 0.0445 M)</em>

<em>∵ Kt = ln ([A₀]/[A]),</em>

∴ (3.36 × 10⁻⁵ s⁻¹)(14100 s) = ln (0.0445 M)/[A]

Taking the exponential of both sides:

1.6 = (0.0445 M)/[A]

<em>∴ [A] = (0.0445 M)/1.6 = 0.0277 M.</em>

<em />

6 0
3 years ago
Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas? a. Mg b. Li c. Al d. Pb
Stells [14]

I believe the answer is A) Mg.

5 0
3 years ago
Read 2 more answers
Sodium metal is sometimes used as a cooling agent in heat exchange units because of its relatively high molar heat capacity of 2
IgorC [24]

Answer:

The specific heat of sodium is 1,23J/g°C

Explanation:

Using the atomic weight of sodium (23g/mol) and the atomic weight definition, we have that each mole of the substance has 23 grams of sodium.

starting from this, we use the atomic weight of sodium to convert the units from J / mol ° C to J / g ° C

28,2 \frac{J}{mol C} x \frac{1mol}{23g} = 1,23 J/g C

4 0
3 years ago
At top, Image 1 shows 2 C's connected by 2 lines. Each C is connected by single lines to 2 H's. At bottom, two dots and 12 C's i
Nana76 [90]

Answer: c

Explanation: Trust me

6 0
2 years ago
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In the decomposition potassium nitride, 10.65 g of nitrogen form. How much potassium nitride was present initially ?
leonid [27]

Answer:

Mass =  99.8 g  

Explanation:

Given data:

Mass of potassium nitride = ?

Mass of nitrogen produced = 10.65 g

Solution:

Chemical equation:

2K₃N→ 6K + N₂

Moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles =  10.65 g / 28 g/mol

Number of moles = 0.38 mol

Now we will compare the moles of nitrogen with potassium nitride.

                        N₂              ;         K₃N

                         1               :            2

                         0.38          :          2×0.38 =0.76

Mass of potassium nitride:

Mass = molar mass × number of moles

Mass =    131.3 g/mol ×   0.76 mol

Mass =  99.8 g    

7 0
3 years ago
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