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viva [34]
3 years ago
14

Are physical properties and chemical properties characteristics used to describe matter

Chemistry
1 answer:
raketka [301]3 years ago
7 0
They both are properties that form the matter which they are today!
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The "hardness" of water describes _____.
krok68 [10]
Your answer is C. its level of dissolved minerals ~A
6 0
3 years ago
Read 2 more answers
explain how energy changes from one form to another in a exothermic reaction. in an endothermic reaction.
Alexxx [7]

Answer:

Exothermic reaction: In exothermic reaction, energy is transferred to the surroundings, and the surrounding temperature increases, this is known as exothermic reaction. In other words energy exits in exothermic reaction. Some example of exothermic reactions are:

1) Neutralisation reaction.

2) Combustion reaction.

3) Some oxidation reaction.

Endothermic reaction: In endothermic reaction, energy is taken in from the surrounding, and the surrounding temperature decreases, this is known as endothermic reaction. In other words energy enters in endothermic reaction. Some example of exothermic reactions are:

1) Thermal decomposition.

2) Reaction between citric acid and sodium hydrogen carbonate.

6 0
3 years ago
Pls help name any of these compounds​
Eva8 [605]

Answer:

D. Propanol

Explanation:

C3H7OH the presence of alcohol functional group makes it propanol

3 0
3 years ago
Which of the drawings contain a mixture?
Assoli18 [71]

the answer is c

Explanation:

because c has all elements mixed together

4 0
3 years ago
G. whose vapour
german

Answer:

8.33 hours

Explanation:

In order to solve this problem, we must apply Graham's law of diffusion in gases. Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its vapour density. For two gases we can write;

R1/R2=√d2/d1

Where;

R1= rate of diffusion of hydrogen

R2= rate diffusion of unknown gas

d1= vapour density of hydrogen

d2= vapour density of the unknown gas

Volume of hydrogen gas = 360cm^3

Time taken for hydrogen gas to diffuse= 1 hour =3600 secs

R1 = 360 cm^3/3600 secs = 0.1 cm^3 s-1

Vapour density of unknown gas = 25

Vapour density of hydrogen = 1

Substituting values,

0.1/R2 = √25/1

0.1/R2 = 5/1

5R2 = 0.1 × 1

R2 = 0.1/5

R2= 0.02 cm^3s-1

Volume of unknown gas = 600cm^3

Time taken for unknown gas to diffuse= volume of unknown gas/ rate of diffusion of unknown gas

Time taken for unknown gas to diffuse= 600/0.02

Time= 30,000 seconds or 8.33 hours

8 0
3 years ago
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