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Ainat [17]
1 year ago
10

Which metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe? auau cucu mnmn agag

Chemistry
1 answer:
Cerrena [4.2K]1 year ago
3 0

Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.

Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.

Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Learn more about electrode here:

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The only way to separate a compound into its elements is by what?
algol [13]
Electrolysis and heat can separate a compound into its elements. 

I hope this helped you!
7 0
3 years ago
An oily liquid with a cheesy, waxy odor like that of goats or other barnyard animals is caproic acid, a compound containing carb
Zinaida [17]

The empirical formula for the caproic acid, given the combustion analysis data is C₃H₆O

We'll begin bey obtaining the mass of carbon, hydrogen and oxygen in the compound. This is illustrated below:

How to determine the mass of C

  • Mass of CO₂ = 9.78 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 9.78

Mass of C = 2.67 g

How to determine the mass of H

  • Mass of H₂O = 20.99 g
  • Molar mass of H₂O = 18 g/mol
  • Molar of H = 2 × 1 = 2 g/mol
  • Mass of H =?

Mass of H = (2 / 18) × 4

Mass of H = 0.44 g

How to determine the mass of O

  • Mass of compound = 4.30 g
  • Mass of C = 2.67 g
  • Mass of H = 0.44 g
  • Mass of O =?

Mass of O = (mass of compound) – (mass of C + mass of H)

Mass of O = 4.30 – (2.67 + 0.44)

Mass of O = 1.19 g

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as follow:

  • C = 2.67 g
  • H = 0.44 g
  • O = 1.19 g
  • Empirical formula =?

Divide by their molar mass

C = 2.67 / 12 = 0.2225

H = 0.44 / 1 = 0.44

O = 1.19 / 16 = 0.074

Divide by the smallest

C = 0.2225 / 0.074 = 3

H = 0.44 / 0.0744 = 6

O = 0.074 / 0.074 = 1

Thus, the empirical formula of the compound is C₃H₆O

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6 0
1 year ago
Which forms of drugs dissolve gradually to release the drug slowly? Check all that apply.
STALIN [3.7K]
<h3><u>Answer;</u></h3>
  • Bead
  • Pellet
  • Wafer
<h3><u>Explanation;</u></h3>
  • Bead is a drug fashioned into small, round objects that dissolve gradually to release the drug slowly
  • Pellet is a drug fashioned into small, bullet-shaped objects that dissolve gradually to release the drug slowly
  • Wafer is a drug fashioned into a thin disk that dissolves gradually to release the drug slowly
4 0
3 years ago
How do I find the over all charge of protons?
d1i1m1o1n [39]
The charge of a proton is always +1
8 0
3 years ago
Read 2 more answers
The atomic number of manganese is 25; its mass number is 55.
Anuta_ua [19.1K]

Answer:

c) 30

Explanation:

In an atom , the relation between the subatomic particles of the atom are given as follows -

For a neutral atom ,

Atomic number = number of protons = number of electrons ,

Mass number = number of protons + number of neutrons,

Hence , from the given information of the question,

Atomic number of Manganese = 25 ,

mass number of Manganese = 55 ,

Now, to calculate the number of neutrons , the above relation can be used -

Mass number = number of protons + number of neutrons,

Rearranging ,

number of neutrons = Mass number - number of protons

substituting the respective values ,

number of neutrons = 55 - 25 = 30 .

4 0
3 years ago
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