Answer:
0.057 M
Explanation:
Step 1: Given data
Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴
Concentration of mercury (II) ion: 0.085 M
Step 2: Write the reaction for the solution of HgBr₂
HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻
Step 3: Calculate the bromide concentration needed for a precipitate to occur
The Ksp is:
Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²
[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M
A. If motion starts and stops at the same location, then the displacment is zero.
D. Distance is always greater than or equal to the magnitutde of the displacement.
Search Results
Featured snippet from the web
A green shirt looks green because light reflects off of the green shirt. ... Visible light on the electromagnetic spectrum is found in between infrared waves and ultraviolet waves.
Answer:
2C3H6 + 9 O2 ---> 6 CO2 + 6 H2O
Explanation:
Answer:
Sorry for disrespecting you but i don't know your language. I want to help but my problem is your language IM SO SORRY
