Answer:
I am also beginners I don't know I am only completing this answer and sorry!!!!!!
Molecular Formula of Propanoic Acid is....
C₃H₆O₂Where;
Atomic Mass of C = 12
Atomic Mass of H = 1
Atomic Mass of O = 6
Substituting Atomic Masses in molecular formula,
(12)₃ + (1)₆ + (16)₂
36 + 6 + 32
74 g/mol
Result:
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,
NO, it should not be the process is still the same . the only factors about it that should change is the experiment itself.:)
Answer:
3CaBr2 + 2LI3PO4 - > Ca3(PO4) 2 + 6LiBr
Explanation:
The first one I did was PO4. There are two on the right side, so I added 2 to Li3PO4 on the other side. That balanced the PO4s and then gave me 6 Lithiums so I balanced that one next on the right side. I added 6 to LiBr which balanced the Li but then gave me 6 Br, so I finished it off by adding 3 in front of CaBr2 which balanced the calcium and bromines.
Here was the process:
CaBr2+2Li3PO4 -> Ca3(PO4)2+LiBr
Balances PO4 (2on both sides)
CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr
Balances Lithiums (6 on each side)
3CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr
Balances Calciums and Bromines (3 Calciums and 6 Bromines each side)
Hope this helped!
9.98 g of NH₃ reacts with 23.4 g of O₂ (up to 3 significant figure).
<h3>What is Significant figures ?</h3>
The digits of a number that are used to express it to the required degree of accuracy, starting from the first non-zero digit.
The given chemical equation ;
4NH₃ + 5O₂ ---> 4NO + 6H₂O
Therefore,
4 moles of NH₃ reacts with 5 moles of O₂.
i.e,
68 g of NH₃ reacts with 160g of O₂.
Therefore,
9.98 g of NH₃ reacts with :
= 160/68 x 9.98
= 23.4 g of O₂ (up to 3 significant figure)
Learn more about Significant figures here ;
brainly.com/question/13386983
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