Acetaldehyde is an organic compound (a compound containing C atoms) composed of a carbonyl group. On the other hand, a carbonyl group is a functional group containing C = O. The hybrid orbitals of a compound determines the number pi and s orbitals in the electronic configuration. For a single bond, there are two s orbitals. For double bonds, on the other hand, the number of s orbital bond is 1 while the number of pi bonds is 2. For triple bonds, there are three pi bonds present in the cloud.
Thus for a c = O bond, the atomic orbital configuration is sp3 containing 1 s orbital and 2 pi bonds.
Answer:
Type: M
Name: Dixytrogen Pentasulfide
Molar Mass:
X*2 = Number * 2 = Number
S*5=32.066*5=160.33
Number + 160.33 = Molar Mass (g/mol).
(The mass for Xytrogen is not present).
Explanation:
Assuming Xytrogen is a non-metal and bonding it with sulfur, another non-metal would make it covalent or molecular.
The name is from the amount of Xs (being two [Di]) and the amount of Ss (being five [Penta]).
The molar mass is explained above. You need to multiply the mass of each element by the number of elements present in the compound. The mass for Xytrogen is not present (as it is a made up element) so I left instructions how to do it once given the mass instruction.
Hope this helps.
Answer:
alkalyene ch2+2n+h wbqlzl
Answer:
Option A. 0.378M
Explanation:
Data obtained from the question include:
Molarity of acid (Ma) =..?
Volume of acid (Va) = 37.0 mL
Volume of base (Vb) = 56.0 mL
Molarity of base (Mb) = 0.250 M
Next, we shall write the balanced equation for the reaction. This is given below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Finally, we can determine the molarity of the acid as shown below :
MaVa/MbVb = nA/nB
Ma x 37 / 0.25 x 56 = 1
Cross multiply
Ma x 37 = 0.25 x 56
Divide both side by 37
Ma = 0.25 x 56 /37
Ma = 0.378M
Therefore, the molarity of the acid, HCl is 0.378M
Answer: The answer is B The kinetic energy breaks the bonds between atoms.
Explanation:
