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Dominik [7]
3 years ago
8

Help me on question 5 pls

Chemistry
1 answer:
Gre4nikov [31]3 years ago
7 0
Ca +2
At -1
In +3
Sr +2
Ra +2
Fr +1
Ba +2
As -3
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Why are covalent bonds between hydrogen and nitrogen or oxygen polar?
yaroslaw [1]

Answer:

The answer to your question is below

Explanation:

Covalent bonds are bonds between to atoms that share a pair of electrons, there are three kinds of covalent bonds but I'll describe only two:

Covalent non polar bond: is a covalent bond between two elements of the same element. Ex two hydrogens, two chlorine, two oxygenes, etc.

Covalent polar bond: is a covalent bond between 2 elements of different elements, for example: hydrogen and chlorine or nitrogen, they are polar because on of the element that form it is smaller than the other one, then a partial positive and a partial negative charge is formed.

6 0
3 years ago
Jenny places a strip of pH paper into a solution. When she removes the pH paper, it has turned yellow-green.
Ronch [10]
Jenny puts the ph paper and lines it up PH SCALE to find how strong the solution.
4 0
3 years ago
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What makes calcium and nitrogen different list two differences
liberstina [14]

Answer:

the difference in electronegativity is so large (2.04) that the bonding electrons spend almost all their time on the nitrogen atom.

Explanation:

Because calcium loses 2 electrons to become Ca2+, and nitrogen gains 3 electrons to become N3−, you need two calcium atoms and three nitrogen atoms in order to form a neutral compound.

6 0
3 years ago
What is in the solar system?
Zina [86]

Answer:

All of the above

Explanation:

All of this is in the solar system.

7 0
2 years ago
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How the calculation of the [OH-], pH and % ionization for 0.619 M ammonia (NH3) NH3 + H2O (liq) rightwards harpoon over leftward
fomenos

Answer:

[OH⁻] = 3.34x10⁻³M; Percent ionization = 0.54%; pH = 11.52

Explanation:

Kb of the reaction:

NH3 + H2O(l) ⇄ NH4+ + OH-

Is:

Kb = 1.8x10⁻⁵ = [NH₄⁺] [OH⁻] / [NH₃]

<em>As all NH₄⁺ and OH⁻ comes from the same source we can write: </em>

<em>[NH₄⁺] = [OH⁻] = X</em>

<em>And as </em>[NH₃] = 0.619M

1.8x10⁻⁵ = [X] [X] / [0.619M]

1.11x10⁻⁵ = X²

3.34x10⁻³ = X = [NH₄⁺] = [OH⁻]

<h3>[OH⁻] = 3.34x10⁻³M</h3><h3 />

% ionization:

[NH₄⁺] / [NH₃] * 100 = 3.34x10⁻³M / 0.619M * 100 = 0.54%

pH:

As pOH = -log [OH-]

pOH = 2.48

pH = 14 - pOH

<h3>pH = 11.52</h3>
5 0
3 years ago
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