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Dominik [7]
3 years ago
8

Help me on question 5 pls

Chemistry
1 answer:
Gre4nikov [31]3 years ago
7 0
Ca +2
At -1
In +3
Sr +2
Ra +2
Fr +1
Ba +2
As -3
You might be interested in
Which of these best describes the particle motion taking place as CO2 gas is exposed to freezing temperatures?
mote1985 [20]
CO2 is carbon dioxide which is most famous for being in gas form so i would figure if it was exposed to freezing temperatures it would turn into a liquid then maybe a solid<span />
5 0
3 years ago
Read 2 more answers
Which choice lists the correct order of the coefficients of each substance in the following neutralization reaction when the equ
Gnoma [55]
The third one you have listed 


4 0
3 years ago
BRAINLIEST TO FIRST CORRECT ANSWER, THANKS!
Tamiku [17]

Answer:

increased

Explanation:

Consuming a compound increases the concentration. When you increase the concentration, the rate constant for that reaction also increases.

5 0
4 years ago
What do you put in the calculator to get the molar mass of Mg3P2
olga55 [171]

Input the atomic masses of Mg and P to give 134.84g/mol

Explanation:

The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance:

When dealing with an element the molar mass is the relative atomic mass expressed as g/mol.

For compounds, you add the atomic masses of the component atoms and you sum up.

You simply input the atomic mass of 3 atoms of Mg and 2 atoms of P

Atomic mass of Mg = 24.3g/mol

                             P = 30.97g/mole

Molar mass of Mg₃P₂ = 3(24.3) + 2(30.97) = 134.84g/mol

learn more:

Molar mass brainly.com/question/2861244

#learnwithbrainly

6 0
3 years ago
What is the temperature of CO2 gas if the average speed (actually the root-mean-square speed) of the molecules is 750 m/s?
erastova [34]

Answer:

992.302 K

Explanation:

V(rms) = 750 m/s

V(rms) = √(3RT / M)

V = velocity of the gas

R = ideal gas constant = 8.314 J/mol.K

T = temperature of the gas

M = molar mass of the gas

Molar mass of CO₂ = [12 + (16*2)] = 12+32 = 44g/mol

Molar mass = 0.044kg/mol

From

½ M*V² = 3 / 2 RT

MV² = 3RT

K = constant

V² = 3RT / M

V = √(3RT / M)

So, from V = √(3RT / M)

V² = 3RT / M

V² * M = 3RT

T = (V² * M) / 3R

T = (750² * 0.044) / 3 * 8.314

T = 24750000 / 24.942

T = 992.302K

The temperature of the gas is 992.302K

Note : molar mass of the gas was converted from g/mol to kg/mol so the value can change depending on whichever one you use.

3 0
3 years ago
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