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gogolik [260]
3 years ago
5

Solve by using substitution. Express your answer as an ordered pair.

Mathematics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

c. 2,4

Step-by-step explanation:

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choli [55]
3:5...added = 8

3/8(2000) = 6000/8 = 750 use brand x aspirin <===
5/8(2000) = 10000/8 = 1250 do not use brand x aspirin
4 0
3 years ago
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I have 28 cubes. how many ten and ones i can make?
Alexandra [31]
2 tens, and 8 ones. I say this because 20 = 10 + 10 so, two tens. 8= 1+1+1+1+1+1+1+1 so, eight ones.
6 0
3 years ago
HELP PLEASE! whats the height and base??
ddd [48]

Answer: 7.5

Step-by-step explanation:

Area of the bottom left triangle = 4x3/2 = 6

Bottom right = 6x3/2 = 9

Top right = 3x4/2 = 6

Top left = 6x3/2 = 9

6+9+6+9 = 30

Each square unit is 4

So the answer should be 30/4 = 7.5

Hope this is correct

8 0
2 years ago
What is the y-coordinate of the solution for the system of equations? x−y=−11 y+7=−2x
ICE Princess25 [194]

Answer:

y= 5

Step-by-step explanation:

Given the system of equations:

x-y=-11

y+7=-2x

In order to find the y coordinate of the solution we must first find the solution to this system of equations. We first start by solving one of the given equations and then substitute the answer of that into the second equation and further solve to get the final answers.

x=y=-11

y+7=-2x

y+7=-2x

+ -7

y = -2x - 7

x - y = -11

y = -2x-7

x-(-2x-7)=-11

x--2x=x+2x=3x

3x+7=-11

-7

-11+-7=-18

3x=-18

\div3

-18\div3=-6

x=-6

y=-2x-7

y=(-2)(-6)-7

-2\times-6=12-7=5

y=5

Hope this helps.

7 0
2 years ago
A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a
UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

P_{t}=P_{0}+500t

Where P_{t} = Population after t years

P_{0}= Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = \frac{5000}{500}

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = \frac{15000}{500}

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = \frac{35000}{500}

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

T_{n}=T_{0}(1+\frac{r}{100})^{t}

T_{n} = Population after t years

T_{0} = Initial population

t = time in years

For double once,

Population after t years = 10000

10000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{10000}{5000}

(1.05)^{t}=2

Take log on both the sides

log(1.05)^{t}=log2

tlog(1.05) = log2

t = \frac{log2}{log1.05}

t = 14.20 years

For double twice,

Population after t years = 20000

20000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{20000}{5000}

(1.05)^{t}=4

Take log on both the sides

log(1.05)^{t}=log4

tlog(1.05) = log4

t = \frac{log4}{log1.05}

t = 28.413 years

For double thrice

Population after t years = 40000

40000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{40000}{5000}

(1.05)^{t}=8

Take log on both the sides

log(1.05)^{t}=log8

tlog(1.05) = log8

t = \frac{log8}{log1.05}

t = 42.620 years

4 0
2 years ago
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