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3 years ago

Help needed now with Math question.

Mathematics

1 answer:

saveliy_v [14]3 years ago

5 0

Answer:

is the last one

Step-by-step explanation:

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A triangle has side lengths measuring 2x + 2 ft x + 3 ft, and

Marta_Voda [28]

Answer:

$3x+5 < n < x-1$

Step-by-step explanation:

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the Triangle Inequality Theorem

1) $(2x+2)+(x+3) > n$

solve for n

$3x+5> n$

Rewrite

$n$

2) $(x+3)+n> 2x+2$

$n> x-1$

therefore

$3x+5 < n < x-1$

5 0

3 years ago

On the map of a town, 1 cm represents 6 miles. Find the distance represented by 4.5 cm. A) 4.5 miles B) 6 miles C) 17 miles D) 2

lora16 [44]

The answer is D) 27 miles because 4.5 * 6 = 27

I hope this helps you out!! <3

4 0

3 years ago

Read 2 more answers

4^x+3 = 2^2(x+1) solve

aleksklad [387]

Answer:

x = 0, 1.32993058

hope this helps :)

Step-by-step explanation:

4 0

3 years ago

An airplane pilot is fertilizing a field. The height y in feet of the fertilizer t seconds after it is dropped is modeled by y(t

zheka24 [161]

Answer:

About 360.178 feet

Step-by-step explanation:

So we want the vertical distance between the fertilizer and the ground to be 0.

This going to be about the time the pilot has dropped it

So we first need to find when y is 0.

$0=-16t^2-3t+300$

We are going to use the quadratic formula to solve for t:

$a=-16$

$b=-3$

$c=300$

The quadratic formula is:

$t=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$t=\frac{3 \pm \sqrt{(-3)^2-4(-16)(300)}}{2(-16)}$

$t=\frac{3 \pm \sqrt{9+19200}}{-32}$

$t=\frac{3 \pm \sqrt{19209}}{-32}$

$t=\frac{3+\sqrt{19209}}{-32} \text{ or } \frac{3-\sqrt{19209}}{-32}$

$t \approx -4.424891774 \text{ or } 4.237391774$

So the pilot has released it at about 4.237391774 seconds since the fertilizer has actually hit the ground at roughly this time.

So we want to know the horizontal distance at t=4.237391774:

$85t$

$85(4.237391774)$

$360.1783008$

360.178 feet

7 0

3 years ago

A gumball machine contains 300 grape flavored balls, 400 cherry flavored balls, and 500 lemon flavored balls. What is the probab

Svet_ta [14]

Answer:

Pr(of getting 1grape ball, 1 cherry ball and 1 lemon ball) =0.20832

Step-by-step explanation:

Let the grape falvored ball be represented by G,

Cherry flavored balls be C

Lemon flavored balls be L

the possible order of picks for getting 1grape ball, 1 cherry ball and 1lemon ball are; GCL or GLC or CGL or CLG or LGC or LCG

Pr(of getting 1grape ball, 1 cherry ball and 1 lemon ball)

= Pr(GCL) or Pr(GLC) or Pr(CGL) or Pr(CLG) or Pr(LGC) or Pr(LCG)

with replacement we have;

Probability = $\frac{number of required outcomes}{number of possible outcomes}$

= $\frac{300}{1200}*\frac{400}{1200}*\frac{500}{1200} +\frac{300}{1200}*\frac{500}{1200}*\frac{400}{1200} +\frac{400}{1200}*\frac{300}{1200}*\frac{500}{1200} \\ \\+\frac{400}{1200}*\frac{500}{1200}*\frac{300}{1200} +\frac{500}{1200}*\frac{300}{1200}*\frac{400}{1200} +\frac{500}{1200}*\frac{400}{1200}*\frac{300}{1200}$

= 0.03472 + 0.03472 +0.03472 + 0.03472 + 0.03472 + 0.03472

=0.20832

3 0

3 years ago