The Gravitational PE (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleration (g), which is 9.81 m/s^2 on Earth’s surface.
so U = mgh = 9.81mh on earth
mass of the car = 50.0 grams = 0.05kg
height, h:
Hill 1 = 90.0 cm = 0.9m,
Hill 2 = 65.0 cm = 0.65m,
Hill 3 = 20.0 cm = 0.2m
substitute into eqn U = mgh
U @ top of Hill 1 = 0.05*9.81*0.9 = 0.4415J
U @ top of Hill 2 = 0.05*9.81*0.65 = 0.3188J
U @ top of Hill 3 = 0.05*9.81*0.2 = 0.0981J
difference in Gravitational Potential Energy from the top of Hill 1 to the top of Hill 3 = 0.4415 - 0.0981
= 0.3434J where J is the unit for energy, Joules
Answer: P= W/t so P=50/20 =2.5 W
First one I believe but im not completely sure
Answer:
There are three main cloud types.
The foundation consists of 10 major cloud types. In addition to cirrus, stratus, cumulus, and nimbus clouds, there are cirrostratus, cirrocumulus, altostratus, altocumulus, stratocumulus, nimbostratus, and cumulonimbus clouds. The following table places these cloud types into the four major cloud groups.
Explanation:
So false, depends what you have learned and your grade level ig
Answer:
D
Explanation:
F = G m1 m2 / r^2 now double r
F = G m1m1/ (2r)^2
F = 1/4 G m1m2/r^2 <===== this is 1/4 of the original
