The image shows metamorphic rock.
2 answers:
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(a) The angular speed of the rotation is 12.57 rad/s
(b) The period of the rotation is 0.5 s.
(c) The speed of the tip of your finger is 15.08 m/s.
<h3>Angular speed of the rotation</h3>The angular speed of the rotation is calculated as follows;
ω = 2πN
where;
- N is number of revolutions
ω = 2π x (2) = 4π = 12.57 rad/s
<h3>Period of rotation</h3>v = ωr
v = 12.57 x 1.2
v = 15.08 m/s
Learn more about angular speed here: brainly.com/question/6860269
Answer:
<em>Both energies are equal when the rock has fallen 20 m or equivalently when it is at a height of 20 m.</em>
Explanation:
<u>Potential and Kinetic Energy</u>
The gravitational potential energy is the energy an object has due to its height above the ground. The formula is
Where:
m = mass of the object
g = acceleration of gravity (9.8~m/s^2)
h = height
Note we can also use the object's weight W=mg into the formula:
The kinetic energy is the energy an object has due to its speed:
Where v is the object's speed.
Initially, the object has no kinetic energy because it's assumed at rest.
The W=30 N rock falls from a height of h=40 m, thus:
Since the sum of the kinetic and potential energies is constant:
U' + K' = 1,200 J
Here, U' and K' are the energies at any point of the motion. Since both must be the same:
U' = K' = 600 J
U'=Wh'=600
Solving for h':
Both energies are equal when the rock has fallen 20 m or equivalently when it is at a height of 20 m.