In the structure shown, each vertices is a carbon atom. for example, the ring has six carbon atoms and the chain has three carbo
n atoms, two of which participate in the triple bond. draw the molecule on the canvas by choosing buttons from the tools (for bonds and charges), atoms, and templates toolbars.
2 answers:
Based on the descriptions, the structural formula is drawn as shown in the attached picture. The ring which is composed of 6 carbon atoms is a cyclic hexane called cyclohexane. The 3-Carbon straight chain attached to the cyclohexane is propyne. The compound has an IUPAC name of propyne cyclohexane.
The structure of the molecule is shown in the attached image.
Further Explanation:
Octet Rule
Each element tends to stabilize itself by bonding with other elements to form compounds. The formation of bonds leads to a decrease in energy that leads to an increase in stability. The bond formation between elements takes place according to the octet rule. This rule states that every element has a tendency to form bonds with other elements so as to attain eight electrons in the valence shell. Almost all elements form bonds in accordance with this rule, except hydrogen. It follows the duplet rule as it can only have a maximum of two electrons in it.
The atomic number of carbon is 6 s its electronic configuration is . It can form four covalent bonds by sharing four electrons. The atomic number of oxygen is 8 and its electronic configuration is
. It needs two more electrons to achieve a stable noble gas configuration of neon.
It is given that each vertex of the diagram represents a carbon atom. There are six carbon atoms in the ring and three carbon atoms are present in the side chain. Out of these three, two carbon atoms participate in the triple bond. The octet of carbon and oxygen is complete in the structure and the duplet of hydrogen is also complete. (For structure, refer to the attached image).
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Answer Details:
Grade: Senior School
Chapter: Molecular structure
Subject: Chemistry
Keywords: carbon, oxygen, triple bond, octet rule, 6, 8, structure.
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This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.
In this case, it is recommended to write the enthalpy for each substance as follows:
Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and and
are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:
It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:
Finally we convert this result to kJ:
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