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krok68 [10]
3 years ago
5

In the structure shown, each vertices is a carbon atom. for example, the ring has six carbon atoms and the chain has three carbo

n atoms, two of which participate in the triple bond. draw the molecule on the canvas by choosing buttons from the tools (for bonds and charges), atoms, and templates toolbars.

Chemistry
2 answers:
Harrizon [31]3 years ago
8 0
Based on the descriptions, the structural formula is drawn as shown in the attached picture. The ring which is composed of 6 carbon atoms is a cyclic hexane called cyclohexane. The 3-Carbon straight chain attached to the cyclohexane is propyne. The compound has an IUPAC name of propyne cyclohexane.

PolarNik [594]3 years ago
8 0

The structure of the molecule is shown in the attached image.

Further Explanation:

Octet Rule

Each element tends to stabilize itself by bonding with other elements to form compounds. The formation of bonds leads to a decrease in energy that leads to an increase in stability. The bond formation between elements takes place according to the octet rule. This rule states that every element has a tendency to form bonds with other elements so as to attain eight electrons in the valence shell. Almost all elements form bonds in accordance with this rule, except hydrogen. It follows the duplet rule as it can only have a maximum of two electrons in it.

The atomic number of carbon is 6 s its electronic configuration is 1{s^2}2{s^2}2{p^2}. It can form four covalent bonds by sharing four electrons. The atomic number of oxygen is 8 and its electronic configuration is 1{s^2}2{s^2}2{p^4}. It needs two more electrons to achieve a stable noble gas configuration of neon.

It is given that each vertex of the diagram represents a carbon atom. There are six carbon atoms in the ring and three carbon atoms are present in the side chain. Out of these three, two carbon atoms participate in the triple bond. The octet of carbon and oxygen is complete in the structure and the duplet of hydrogen is also complete. (For structure, refer to the attached image).

Learn More:

  1. What is the main purpose of conducting experiments? brainly.com/question/5096428
  2. What is the percentage error in the experiment? brainly.com/question/11181911

Answer Details:

Grade: Senior School

Chapter: Molecular structure

Subject: Chemistry

Keywords: carbon, oxygen, triple bond, octet rule, 6, 8, structure.

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3 years ago
Bromination occurs on alkene functional groups, but NOT on alkenes found within aromatic functional group, such as the phenyl ri
liq [111]

Answer:

When cinnamic acid react with bromine ,addition reaction rapidly occur on alkene functional group to form dibromo product

Explanation:

Phenyl ring is an aromatic hydrocarbon ,when aromatic hydrocarbons react with Cl2,Br2 or KMnO4 no reaction occur ,where as unsaturated hydrocarbon  like alkene react .Aromatic hydrocarbon with these reagents undenr different conditions undergoes subtituition reaction.They react with bromine in presence of lewis acid catalyst ferric bromide.

8 0
3 years ago
If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?
Pie

<u><em>Answer:</em></u>

m = \frac{E}{c^2}

c = \sqrt{\frac{E}{m} }

E = 12.8 J

<u><em>Explanation:</em></u>

<u>Part 1: Solving for m</u>

<u>We are given that:</u>

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

m = \frac{E}{c^2}

<u>Part 2: Solving for c</u>

<u>We are given that:</u>

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

c^2 = \frac{E}{m}\\  \\ c=\sqrt{\frac{E}{m}}

<u>Part 3: Solving for E</u>

<u>We are given that:</u>

m = 80 and c = 0.4

<u>To get the value of E, we will simply substitute in the given equation: </u>

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

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Answer:

pI = 6.16

Explanation:

The pI is given by the average of the pKas that are involved. In this case,

Pka of carboxylic acid was given as 2.72 and that of the Amino group was given as 9.60. the average would then be ½(2.72+9.60)

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