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krok68 [10]
3 years ago
5

In the structure shown, each vertices is a carbon atom. for example, the ring has six carbon atoms and the chain has three carbo

n atoms, two of which participate in the triple bond. draw the molecule on the canvas by choosing buttons from the tools (for bonds and charges), atoms, and templates toolbars.

Chemistry
2 answers:
Harrizon [31]3 years ago
8 0
Based on the descriptions, the structural formula is drawn as shown in the attached picture. The ring which is composed of 6 carbon atoms is a cyclic hexane called cyclohexane. The 3-Carbon straight chain attached to the cyclohexane is propyne. The compound has an IUPAC name of propyne cyclohexane.

PolarNik [594]3 years ago
8 0

The structure of the molecule is shown in the attached image.

Further Explanation:

Octet Rule

Each element tends to stabilize itself by bonding with other elements to form compounds. The formation of bonds leads to a decrease in energy that leads to an increase in stability. The bond formation between elements takes place according to the octet rule. This rule states that every element has a tendency to form bonds with other elements so as to attain eight electrons in the valence shell. Almost all elements form bonds in accordance with this rule, except hydrogen. It follows the duplet rule as it can only have a maximum of two electrons in it.

The atomic number of carbon is 6 s its electronic configuration is 1{s^2}2{s^2}2{p^2}. It can form four covalent bonds by sharing four electrons. The atomic number of oxygen is 8 and its electronic configuration is 1{s^2}2{s^2}2{p^4}. It needs two more electrons to achieve a stable noble gas configuration of neon.

It is given that each vertex of the diagram represents a carbon atom. There are six carbon atoms in the ring and three carbon atoms are present in the side chain. Out of these three, two carbon atoms participate in the triple bond. The octet of carbon and oxygen is complete in the structure and the duplet of hydrogen is also complete. (For structure, refer to the attached image).

Learn More:

  1. What is the main purpose of conducting experiments? brainly.com/question/5096428
  2. What is the percentage error in the experiment? brainly.com/question/11181911

Answer Details:

Grade: Senior School

Chapter: Molecular structure

Subject: Chemistry

Keywords: carbon, oxygen, triple bond, octet rule, 6, 8, structure.

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Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
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