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saul85 [17]
3 years ago
13

In France, grapes are 1.75 Euros per kilogram. What is the cost of grapes in dollars per pound if the exchange rate is 1.36 doll

ars to 1 Euro? ( Hint: covert 1 until at a time.) ( Remember: 1 1b =454g)
Chemistry
1 answer:
Jet001 [13]3 years ago
3 0

You want to convert Euros / kg to Dollars / pound

 

So you'll have to multiply the price (Euros / kg) by the exchange rate (Dollars / Euro) to get a number that has units of Dollars / kg.

 

Euros     Dollars       Dollars

-------  x ---------   =  --------

 kg         Euro             kg

 

Then you have to multiply the number of kg in a pound (which has units of kg / pound) to get a number in units of Dollars / pound.  This number is 2.2.

 

Dollars       kg              Dollars

--------  x --------   =      --------

  kg        pound           pound

 

So the answer would be 1.75 * 1.36 / 2.2 = 1.08 dollars / pound.

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The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

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Consider the equation of the reaction between NaOH and $HCl$

  NaOH (aq) + HCl (aq) → NaCl(aq) + $H_2O (l)$

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If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$  mole/L

The volume of NaOH added up to the color change = $V_2 \text{  and conc of NaOH = M}_2$ mole/L

Moles of $HCl$ taken = $V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$  moles.

The color change will occur when the moles of NaOH added is equal to the moles of $HCl$ taken.

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When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$, then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$)

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