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3 years ago

Can Someone help me pls?

Chemistry

1 answer:

Ilia_Sergeevich [38]3 years ago

8 0

Answer:

For H3O concentration you do 10^-pH so if pH is 5 then H3O+ is 10^-5= 1*10^-5 H3O+ ions

For OH is one extra step. First find H3o+ ions using equation above then you have to use that to divide 1*10^-14

So if pH is 5....the H3O+ is 1*10^-5 then OH- = (1*10^-14)/(1*10^-5) = 1*10^-9 OH ions

as far as acid/base pH 0-6 is Acid 8-14 is Base. pH of 7 is neutral. Recheck your work *hint* *hint* water is neutral. Spit is above 7 so is base.

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A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at

balandron [24]

Answer:

The final temperature of the water is 22.44°C.

Explanation:

Heat lost by tin will be equal to heat gained by the water

$-q_1=q_2$

Mass of tin = $m_1=18.5 g$

Specific heat capacity of tin = $c_1=0.21 J/g^oC$

Initial temperature of the tin = $T_1=97.38^oC$

Final temperature = $T_2$ =T

$q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=75.7 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=21.52^oC$

Final temperature of water = $T_2$ =T

$q_2=m_2c_2\times (T-T_3)$

$-q_1=q_2$ (Law of Conservation of energy)

$-(m_1\times c_1\times (T-T_1))=m_2\times c_2\times (T-T_3)$

On substituting all values:

$-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)$

we get, T = 22.44°C

The final temperature of the water is 22.44°C.

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If the density of blood is 1. 060 g/ml. What is the mass of 6. 56 pints of blood?

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Answer:

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Explanation:

6.56 pints * 473.1765 ml/pint * 1.060 g/ml = 3290 gm

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Answer:

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Answer:

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