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shepuryov [24]
3 years ago
11

Can Someone help me pls?

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

For H3O concentration you do 10^-pH so if pH is 5 then H3O+ is 10^-5= 1*10^-5 H3O+ ions

For OH is one extra step. First find H3o+ ions using equation above then you have to use that to divide 1*10^-14

So if pH is 5....the H3O+ is 1*10^-5 then OH- = (1*10^-14)/(1*10^-5) =  1*10^-9 OH ions

as far as acid/base pH 0-6 is Acid 8-14 is Base. pH of 7 is neutral. Recheck your work *hint* *hint* water is neutral. Spit is above 7 so is base.

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Answer:

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For the hydrated compound, let us denote is by Na₂CO₃.xH₂O

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Given values:

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To determine the integer x, we find the number of moles of the anhydrous Na₂CO₃ and that of the water of crystallisation:

        Number of moles  = \frac{mass }{molar mass }

Molar mass of Na₂CO₃ =[(23x2) + 12 + (16x3)]  = 106gmol⁻¹

Molar mass of H₂O = [(1x2) + (16)] = 18gmol⁻¹

Number of moles of Na₂CO₃ = \frac{3.22}{106} = 0.03mole

Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

From the obtained number of moles:

                          Na₂CO₃                               H₂O

                           0.03                                    0.06

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Ratio                  0.03/0.03                         0.03/0.06

                                 1                                      2

Therefore, x = 2    

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