Answer:
B. CH3COOH pH > 4.7 (4.8)
Explanation:
- CH3COOH + NaOH ↔ CH3COONa + H2O
- CH3COONa + NaOH ↔ CH3COONa
∴ mol NaOH = (5 E-3 L)*(0.10 mol/L) = 5 E-4 mol
⇒ mol CH3COOH = (0.05 L)*(0.20 mol/L) = 0.01 mol
⇒ <em>C</em> CH3COOH = (0.01 mol - 5 E-4 mol) / (0.105 L)
⇒ <em>C</em> CH3COOH = 0.0905 M
∴ mol CH3COONa = (0.05 L )*(0.20 mol/L) = 0.01 mol
⇒ <em>C</em> CH3COONa = (0.01 mol + 5 E-4 mol) / (0.105 L )
⇒ <em>C</em> CH3COONa = 0.1 M
∴ Ka = ([H3O+]*(0.1 + [H3O+])) / (0.0905 - [H3O+]) = 1.75 E-5
⇒ 0.1[H3O+] + [H3O+]² = (1.75 E-5)*(0.0905 - [H3O+])
⇒ [H3O+]² 0.1[H3O+] = 1.584 E-6 - 1.75 E-5[H3O+]
⇒ [H3O+]² + 0.1000175[H3O+] - 1.584 E-6 = 0
⇒ [H3O+] = 1.5835 E-5 M
∴ pH = - Log [H3O+]
⇒ pH = - Log (1.5835 E-5)
⇒ pH = 4.8004 > 4.7
Answer:
3
Explanation:
At pH 3, the pentapeptide Ala-Glu-His-Val-Cys would contain two positively charged groups and one negatively charged group.
This is evident in that peptides have both carboxylic and amino groups.
Given that peptides have a certain amount of H⁺ and OH⁻ ions, it converts to zwitterions.
This conversion process is based on pKₐ and pKb of the acid and the base accordingly.
Therefore, they have two positively charged groups and one negatively charged grou
Answer:
ions
Explanation:
An atom that has gained or lost an electron is called an ion. Ions are charged particles that have lost or added an electron to their outermost shell. Ions are the basis of any chemical reaction. The combination of ions leads to the formation of bonds between atoms and this results in molecules and compounds.
When atoms are in their ground state, they are otherwise neutral and such would not combine chemically. It is difficult to find elements in such form naturally. Atoms that have ionized by losing or gaining electrons would freely combine with one another in order to establish a more stable configuration.
Answer:
The density remains the same
Explanation:
The density remains the same because cutting the object in half will divide the mass & volume by the same amount. The density cant be changed no matter what happens to it.
If you need help reading it then ask away, the two answers end up being, 2Na, and 2NO3
