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Lostsunrise [7]
2 years ago
6

MARKING BRAINLIEST

Chemistry
1 answer:
Evgesh-ka [11]2 years ago
6 0

Answer:

I LIKE TRAINS

Explanation:

SNAILS ARE YUMMY

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an element "x" has the election configuration 2,8,3 this element is found in ______group and_____period A.3,llla B.llla,3 C.vlla
iogann1982 [59]

This element is found in group 3A, period 3

<h3>Further explanation </h3>

The maximum number of electrons that can be filled in the nth electron shell is 2n²(n=shell)

  • K shell (n = 1) maximum 2 x 1² = 2 electrons
  • L shell (n = 2) maximum 2 x 2² = 8 electrons
  • M shell (n = 3) maximum 2 x 3² = 18 electrons
  • N shell (n = 4) maximum 2 x 4² = 32 electrons

Electron configuration of element X : 2.8.3 , so :

K shell = 2 ⇒1s²

L shell = 8⇒2s²2p⁶

M shell = 3⇒ 3s²3p¹

Block p: group 13-18 (has a 2p-6p configuration), also called a representative element because it includes metals, non-metals and metalloids

The outer shell 3s²3p¹ : located in group 3A and period 3

group⇒valence electron ⇒3

period⇒the greatest value of the quantum number n⇒3

3 0
3 years ago
NEED ASAP!!! Several samples of a solid was measured to have these masses and volumes listed in the
sammy [17]
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8 0
3 years ago
If a dog has a mass of 16.1 kg, what is its mass in the following units? Use scientific notation in all of your answers.
nekit [7.7K]

Answer:

16.1\times 10^3\ \text{g}

16.1\times 10^{6}\ \text{mg}

16.1\times 10^{9}\ \mu\text{g}

Explanation:

Mass of dog = 16.1\ \text{kg}

1\ \text{kg}=10^{3}\ \text{g}

1\ \text{kg}=10^{6}\ \text{mg}

1\ \text{kg}=10^{9}\ \mu\text{g}

So,

16.1\ \text{kg}=16.1\times 10^3\ \text{g}

16.1\ \text{kg}=16.1\times 10^{6}\ \text{mg}

16.1\ \text{kg}=16.1\times 10^{9}\ \mu\text{g}

Mass of the dog in the other units is 16.1\times 10^3\ \text{g}, 16.1\times 10^{6}\ \text{mg} and 16.1\times 10^{9}\ \mu\text{g}.

3 0
3 years ago
Tell me a funny joke
nasty-shy [4]

Answer:

Explanation:

lol, i tried

dont report, as this is related to math

8 0
3 years ago
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How many liters of N2 are needed to react with 92 g of K, at STP, according to the following reaction? (Balance equation first.)
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2 years ago
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