• Take a look at the steps below to see how to balance this equation. Let's start by writing the unbalanced equation given the information.
Unbalanced Equation : C₃H₈ (g) + O₂ (g) → CO₂ (g) + H₂O (g)
,
Start by Balancing the Carbons : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + H₂O (g)
Now let's balance the Hydrogen : C₃H₈ (g) + O₂ (g) → 3CO₂ (g) + 4H₂O (g)
Balancing the Oxygen : C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)
Balanced Equation : C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g)
• Let's apply dimensional analysis here,
0.7 L propane × (5 liters Oxygen / 1 liter Propane) = 3.5 Liters of Oxygen
• Similarly we can identify the liters of carbon dioxide produced in the reaction,
0.7 L propane × (3 liters Carbon Dioxide / 1 liter Propane) = 2.1 Liters of Carbon Dioxide
• 0.7 L propane × (4 liter water vapor / 1 liter propane ) = 2.8 Liters of Water Vapor
Answer:
Both have the same balance on a weight with. 2 dimensional figures on the area formula
Explanation:
Answer:
Energy will enter the peas from the water
Explanation:
An exothermic process would occur as the energy gathered by the heated water is transferred to the peas.
Answer:
1.635 M
Explanation:
Given:
10 mL of 20 volumes Hydrogen Peroxide
Here,
20 volumes of Hydrogen Peroxide means that on decomposition of 1 mL of H₂O₂ 20 mL of O₂ is obtained
also,
means 1 dm³ of H₂O₂ solution produces 20 dm³ oxygen
Now,
at 298K and 1 atm
20 dm³ oxygen = 
moles
or
= 0.817 moles
also,
2H₂O₂ → 2H₂O + O₂
thus,
1 dm³ of solution must contain 2 × moles of O₂ as moles of H₂O₂
thus,
Number of moles of H₂O₂ = 2 × 0.817
or
Number of moles of H₂O₂ = 1.635 moles
Hence,
For 20 volume hydrogen peroxide is 1.635 M
