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Alona [7]
3 years ago
10

The concentration of dye in Solution A is 25.527 M. You have 13 mL of water at your disposal to make the dilutions. The solution

is diluted twice, to make Solutions B and C. In the first dilution, 8 parts of Solution A is diluted with 12 parts water to make Solution B. In the second dilution, 8 parts of Solution B is diluted with 4 parts water to make Solution C. What is the concentration of dye in Solution C
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
7 0

Answer:

 38825.472 M

Explanation:

Using

C1V1=C2V2

To make solution B,

C1 = 25.527 M, V1 = 13 mL

C2 = 25.527 x 8 = 204.216 M

V2 = 13 X 12 = 156 mL

To make solution C'

C1 = 8 X 202.216 M = 1617.728

V1 = 8 X 156mL = 1248 mL

V2 = 4 X 13 = 52 mL

C2 = C1V1 / V2

    =1617.728 X 1248 / 52

 =38825.472 M

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Answer:

Cr(OH)2(s), Na+(aq), and NO3−(aq)

Explanation:

Let is consider the molecular equation;

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This is a double displacement or double replacement reaction. The reacting species exchange their partners. We can see here that both the sodium ion and chromium II ion both exchanged partners and picked up each others partners in the product.

Sodium ions and nitrate ions now remain in the solution while chromium II hydroxide which is insoluble is precipitated out of the solution as a solid hence the answer.

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4 years ago
A sample of gas initially has a volume of 2.25 L at 350 K and a pressure of 1.75 atm. What will be sample pressure if the volume
IRINA_888 [86]

Answer:

8.44 atm

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2.25 L

Initial temperature (T₁) = 350 K

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Final volume (V₂) = 1 L

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The final pressure of the gas can be obtained as illustrated below:

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Cross multiply

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350 × P₂ = 2953.125

Divide both side by 350

P₂ = 2953.125 / 350

P₂ = 8.44 atm

Thus, the final pressure of the gas is 8.44 atm.

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