Antimony also forms trihalides and pentahalides, such as SbF3 , where its oxidation state is +3, and SbF5 , where its oxidation state is +5
Answer:
The final temperature of the mixture is 22.3°C
Explanation:
Assuming that the 120 g substance at 80°C is water, final temperature of the mixture can be determined using the formula:
Heat lost = Heat gained
Heat = mc∆T where m is mass, c is specific heat capacity of water, and ∆T is the temperature change =<em> Tfinal - Tinitial</em>.
Let the final temperature be T
Heat lost = 120 × c × (T - 80)
Heat gained = 3000 × c × ( T - 20)
Equating the heat lost and heat gained
120 × c × -(T - 80) = 3000 × c × (T - 20)
9600 - 120T = 3000T - 60000
60000 + 9600 = 3000T + 120T
69600 = 3120T
T = 69600/3120
T = 22.3°C
Therefore, the final temperature of the mixture is 22.3°C
1) Cellulose - extracellular location, glycosidic bond, β-linkage. Cellulose is polysaccharide composed of glucose linked with β-1,4 bons.
2) Messenger RNA - informational macromolecule, phosphodiester bridge, helical structure possible, synthesis requires a template. mRNA is nucleic acid, <span> mRNA is </span>translated<span> into a polymer of amino acids.</span><span>
3) </span>Globular protein - peptide bond, helical structure possible, synthesis requires a template. Protein is composed of amino acid linked with peptide bond, secundary structure can be α-helix, gene expression.<span>
4) </span>Amylopectin - branched-chain polymer, glycosidic bond, helical structure possible. Amylopectin is subunit of starch, sugar with α-1,4 and α-1,6 glycosidic bonds.<span>
5) DNA - i</span>nformational macromolecule, phosphodiester bridge, helical structure possible, synthesis requires a template, nucleoside triphosphate. DNA is helical <span>chain of </span>nucleotides<span> carrying the </span>genetic<span> instructions.</span>
6) Fibrous protein - peptide bond, helical structure possible. Protein is composed of amino acid linked with peptide bond
Answer:
Explanation:
In this case, Gay-Lussac's law is used to compute the required temperature, as it relates pressure and temperature, by knowing that the atmospheric standard temperature is 25 °C, as follows:
Thus, the initial pressure is known as 14.7 psi and the initial temperature 25 °C, which correspond to the atmospheric conditions. Nonetheless, the pressure into the cooker, should be:
Since the 12.5 psi are above the atmospheric pressure. In such a way, the temperature inside the cooker turns out:
Best regards.