4 moles of NaOH is present in the given 160 grams of NaOH.
<h3>How we calculate moles?</h3>
Moles of any substance will be calculated as:
n = W/M, where
W = given mass of NaOH = 160 grams (given)
M = molar mass of NaOH = 40 g/mole
Moles of NaOH is calculated as:
n = 160g / 40g/mol = 4 moles
Hence, moles of sodium hydroxide (NaOH) is 4 moles.
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Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.
Molarity :
It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .
It uses unit M or 
It can be formulated as :

Given : mol of MgCl₂ (solute ) = 0.50 mol
Volume of solution = 750 mL
Following steps can be done :
Step 1 ) To convert volume of solution from mL to L
1 L = 1000 mL

Volume of solution = 0.750 L
Step 2) To find molarity
Plugging mole of solute and volume of solution in molarity formula as :


Hence molarity of MgCl₂ solution is 0.67 M
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