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3 years ago

Definition of deposition in science

2 answers:

7 0

Wikipedia say, "Deposition is the geological process in which sediments, soil and rocks are added to a land form or land mass. Wind, ice, water, and gravity transport previously weathered surface material, which, at the loss of enough kinetic energy in the fluid, is deposited, building up layers of sediment" Hopefully this helps:) Plze mark me brainiest!

marin [14]3 years ago

5 0

The settling of particles or sediment onto a surface. The particles may originate from a vapor, solution, a suspension, or a mixture.

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How do you differentiate between gas and a vapour ?

kolbaska11 [484]

Gas is a substance that will not phase change.

And vapor is a substance above it's boiling point temperature.

6 0

3 years ago

Hey can anyone explain this .<br>How to make covalent bond of Oxygen ??

viva [34]

Answer:

Explanation:

A covalent bond is where electrons are shared equally between molecules. if you see the bottom of the page each oxygen is missing 2 electrons so they share two of one of their own with eachother and give oxygen a full octet. it doesnt have to be full to be a covallent bond but it just has to share them evenly rather than keep it to themselves

3 0

3 years ago

Iodine-131 is a radioactive isotope that is used in the treatment of cancer of the thyroid. The natural tendency of the thyroid

Finger [1]

Answer:

a) Binding Energy = 1084.266 MeV

b) Binding energy per nucleon = 8.28 MeV

Explanation:

Binding Energy, $BE = \triangle M * 931.5$

Where ΔM = Mass defect of Iodine-131

The mass of iodine-131 = 130.906124 u.

Number of protons in Iodine-131 = 53

Number of neutrons in Iodine-131 = 78

Mass of a proton = 1.007276 u

Mass of neutron = 1.008664 u

Total mass of the 53 protons in Iodine-131 = (53*1.007276)

Total mass of the 53 protons in Iodine-131 = 53.39 u

Total mass of the 78 protons in Iodine-131 = (78*1.008664)

Total mass of the 78 protons in Iodine-131 = 78.68 u

$\triangle M = (53.39 + 78.68) - 130.906124\\\triangle M = 1.164 u$

Binding Energy = 1.164 * 931.5

Binding Energy = 1084.266 MeV

b) Binding Energy per nucleon

The mass of the nucleon of iodine 131 = 130.906124

Binding Energy per nucleon = 1084.266/130.906124

Binding energy per nucleon = 8.28 MeV

5 0

4 years ago

What is the another another name of lithium carbonate

sveta [45]

Answer:

Lithium carbonate

✌️✌️

3 0

3 years ago

The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr

jenyasd209 [6]

Answer : The final temperature of the water is, $22.5166^oC$

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

$\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole$

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

$2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ$

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives $\frac{6542 kJ}{2}\times 0.1103=360.7913kJ$ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : $q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})$

where,

$q_w$ = heat released = 360.7913 kJ = 36079.13 J

$m_w$ = mass of water = 5691 g

$c_w$ = specific heat of water= $4.18J/g^oC$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $21^oC$

Now put all the given values in the above formula, we get:

$36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)$

$T_{final}=22.5166^oC$

Therefore, the final temperature of the water is, $22.5166^oC$

8 0

4 years ago

Definition of deposition in science​

Definition of deposition in science