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fiasKO [112]
3 years ago
8

Definition of deposition in science​

Chemistry
2 answers:
mart [117]3 years ago
7 0

Wikipedia say, "Deposition is the geological process in which sediments, soil and rocks are added to a land form or land mass. Wind, ice, water, and gravity transport previously weathered surface material, which, at the loss of enough kinetic energy in the fluid, is deposited, building up layers of sediment" Hopefully this helps:) Plze mark me brainiest!

marin [14]3 years ago
5 0

The settling of particles or sediment onto a surface. The particles may originate from a vapor, solution, a suspension, or a mixture.

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Which statement below about contrasting Hb and Mb is FALSE?
olchik [2.2K]

Answer:

C. Hb binds O2 more tightly than Mb.

Explanation:

<u>Hb and Mb are both oxygen carrier protiens which contain the heme group. Hb has 4 heme units in 1 moleucle which work via coperative effect. On the other hand, Mb has only one heme unit. </u>

<u>From above theory, statement A and B are correct.</u>

<u>Although the heme group of the Mb is identical to those of Hb, Mb has a higher affinity for carrying oxygen than hemoglobin.</u>

<u>Hence, Statement C is wrong.</u>

Thats why the function of hemoglobin is to transport oxygen and that of myoglobin is to store oxygen.

<u>When a curve is plotted between oxygen accepted and the pressure of the oxygen, Hb shows sigmoidal, whereas Mb shows hyperbolic oxygen saturation curves.</u><u> The statement D is correct.</u>

<u>Bohr effect and various factors decribe the statement : Hb-oxygen binding is dependent on physiological changes in pH, whereas Mb-oxygen binding is not. </u><u>The  statement E is also correct.</u>

7 0
3 years ago
Which ion La3+ or Lu3+ will form the more stable complex with EDTA4-
shepuryov [24]
I don’t really know but I’ll get someone to help u
6 0
3 years ago
What is Magnitude?<br>⚫ No Spam​
Rainbow [258]

the great size or extent of something

4 0
3 years ago
Read 2 more answers
A mixture of helium and methane gases, at a total pressure of 821 mm Hg, contains 0.723 grams of helium and 3.43 grams of methan
Nookie1986 [14]

<u>Answer:</u>

<u>For 1:</u> The partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

<u>For 2:</u> The mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

<u>Explanation:</u>

<u>For 1:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For helium:</u>

Given mass of helium = 0.723 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

\text{Moles of helium}=\frac{0.723g}{4g/mol}=0.181mol

  • <u>For methane gas:</u>

Given mass of methane gas = 3.43 g

Molar mass of methane gas = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane gas}=\frac{3.43g}{16g/mol}=0.214mol

To calculate the mole fraction , we use the equation:

\chi_A=\frac{n_A}{n_A+n_B}     .......(2)

To calculate the partial pressure of gas, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}       ......(3)

  • <u>For Helium gas:</u>

We are given:

n_{He}=0.181mol\\n_{CH_4}=0.214mol

Putting values in equation 2, we get:

\chi_{He}=\frac{0.181}{0.181+0.214}=0.458

Calculating the partial pressure by using equation 3, we get:

p_T=821mmHg\\\\\chi_{He}=0.458

Putting values in equation 3, we get:

p_{He}=0.458\times 821mmHg=376mmHg

  • <u>For Methane gas:</u>

We are given:

n_{He}=0.181mol\\n_{CH_4}=0.214mol

Putting values in equation 2, we get:

\chi_{CH_4}=\frac{0.214}{0.181+0.214}=0.542

Calculating the partial pressure by using equation 3, we get:

p_T=821mmHg\\\\\chi_{CH_4}=0.542

Putting values in equation 3, we get:

p_{CH_4}=0.542\times 821mmHg=445mmHg

Hence, the partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

  • <u>For 2:</u>

We are given:

Partial pressure of nitrogen gas = 363 mmHg

Partial pressure of carbon dioxide gas = 564 mmHg

Total pressure = (363 + 564) mmHg = 927 mmHg

Calculating the mole fraction of the gases by using equation 3:

<u>For nitrogen gas:</u>

363=\chi_{N_2}\times 927\\\\\chi_{N_2}=\frac{363}{927}=0.392

<u>For carbon dioxide gas:</u>

564=\chi_{CO_2}\times 927\\\\\chi_{CO_2}=\frac{564}{927}=0.608

Hence, the mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

6 0
3 years ago
If the input force applied to one end of a first-class lever is 8 N, and the fulcrum is located 6 m away from the input force bu
MatroZZZ [7]

Answer:

16 N

Explanation:

The ratio of output force to the input force is called mechanical advantage of the lever. Also, the ratio of input arm distance to the output arm distance is called mechanical advantage of the lever.

We have,

Input force = 8 N

Input arm distance = 6 m

Output arm distance = 3 m

We need to find the resulting output force. So,

\dfrac{F_o}{8}=\dfrac{6}{3}\\\\F_o=16\ N

So, the resulting output force is 16 N.

4 0
3 years ago
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